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iragen [17]
2 years ago
6

an object is thrown straight up. which of the following is true abought the sign of workdone by the force of gravity on the obje

ct, while the object moves up and then down
Physics
1 answer:
aliya0001 [1]2 years ago
6 0

Answer:

Upward: Negative

Downward: Positve

Explanation:

Let upward be positive

We want to find the work done on the object upwards.

The equation of work done due to gravity is

f _{g}d \cos( \alpha )

It is read as force of gravity times displacement times cos of the angle between the force and displacement.

Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so

f_{g}d \cos(180)

Cosine of 180 is -1

so

-  f_{g}d

If we go downwards, the sign will be positive because cos(0)=1

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A large aquarium of height 6 m is filled with fresh water to a depth of D = 1.50 m. One wall of the aquarium consists of thick p
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Answer

given,

height of aquarium = 6 m

Depth of fresh water = D = 1.50 m

horizontal length of the aquarium(w) = 8.40 m

total force increased when liquid is filled to depth = 4.30 m

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ρ = 998 Kg/m³

force in the aquarium.

dF = PdA

F = \int PdA

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F = \rho\ g\ w \int ydy

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At D = 1.5 m

F = \dfrac{980\times 9.8\times 8.4\times 1.5^2}{2}

F = 9.08 x 10⁴ N

At D = 4.30 m

F = \dfrac{980\times 9.8\times 8.4\times 4.3^2}{2}

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Total force on the wall increased by

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A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the
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Answer:

2.82 s

Explanation:

The ball will be subject to the acceleration of gravity which can be considered constant. Therefore we can use the equation for uniformly accelerated movement:

Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2

Y0 is the starting position, 2.3 m in this case.

Vy0 is the starting speed, 13 m/s.

a will be the acceleration of gravity, -9.81 m/s^2, negative because it points down.

Y(t) = 2.3 + 13 * t - 1/2 * 9.81 * t^2

It will reach the ground when Y(t) = 0

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