Answer:
10604 square meters
Explanation:
0.23 cm = 0.0023m
Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.
With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane 
. And mass of the water displaced is its volume V times its density 
We assume the carrier has a shape of a rectangular box, so this extra displaced volume is the extra depth d = 0.0023 m times cross-section area A
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Explanation:
The first thing we must do for this case is the sum of forces in a horizontal direction.
We have then:
Substituting values we have:
From here, we clear the mass of the object:
We now look for the weight of the object.
Where,
g: acceleration of gravity (9.8 m/s^2)
Substituting values:
Answer:
the weight of the object is:
option 4
Answer:
Explanation:
Range of projectile R = 20 m
formula of range
R = u² sin2θ / g
u is initial velocity , θ is angle of projectile
putting the values
20 = u² sin2x 40 / 9.8
u² = 199
u = 14.10 m /s
At the initial point
vertical component of u
= u sin40 = 14.1 x sin 40
= 9.06 m/s
Horizontal component
= u cos 30
At the final point where the ball strikes the ground after falling , its speed remains the same as that in the beginning .
Horizontal component of velocity
u cos 30
Vertical component
= - u sin 30
= - 9.06 m /s
So its horizontal component remains unchanged .
change in vertical component = 9.06 - ( - 9.06 )
= 18.12 m /s
change in momentum
mass x change in velocity
= .050 x 18.12
= .906 N.s
Impulse = change in momentum
= .906 N.s .
Mostly gravity voloume and sometimes what it is made of
