Well one is from potential energy to ascensive moving energy . And another is from electrical to circuit energy.
Answer
given,
height of aquarium = 6 m
Depth of fresh water = D = 1.50 m
horizontal length of the aquarium(w) = 8.40 m
total force increased when liquid is filled to depth = 4.30 m
g = 9.81 m/s²
ρ = 998 Kg/m³
force in the aquarium.
dF = PdA





At D = 1.5 m

F = 9.08 x 10⁴ N
At D = 4.30 m

F = 7.46 x 10⁵ N
Total force on the wall increased by
ΔF = 74.6 x 10⁴ - 9.08 x 10⁴
ΔF = 65.52 x 10⁴ N
<span>The overall force that is acting on the bottle is gravity. With the incline being 30 degrees the full force of gravity isn't acting on the bottle becuase the ramp isn't allowing the bottle to go straight down. By taking the sin of 30 degrees you find the proportion of gravity that is acting on the bottle to be 4.9 meters per second and the bottle weights 20 kg so the force acting on the bottle is 98 Newtons.</span>
Answer:
2.82 s
Explanation:
The ball will be subject to the acceleration of gravity which can be considered constant. Therefore we can use the equation for uniformly accelerated movement:
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 is the starting position, 2.3 m in this case.
Vy0 is the starting speed, 13 m/s.
a will be the acceleration of gravity, -9.81 m/s^2, negative because it points down.
Y(t) = 2.3 + 13 * t - 1/2 * 9.81 * t^2
It will reach the ground when Y(t) = 0
0 = 2.3 + 13 * t - 1/2 * 9.81 * t^2
-4.9 * t^2 + 13 * t + 2.3 = 0
Solving this equation electronically gives two results:
t1 = 2.82 s
t2 = -0.17 s
We disregard the negative solution. The ball spends 2.82 seconds in the air.