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iragen [17]
2 years ago
6

an object is thrown straight up. which of the following is true abought the sign of workdone by the force of gravity on the obje

ct, while the object moves up and then down
Physics
1 answer:
aliya0001 [1]2 years ago
6 0

Answer:

Upward: Negative

Downward: Positve

Explanation:

Let upward be positive

We want to find the work done on the object upwards.

The equation of work done due to gravity is

f _{g}d \cos( \alpha )

It is read as force of gravity times displacement times cos of the angle between the force and displacement.

Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so

f_{g}d \cos(180)

Cosine of 180 is -1

so

-  f_{g}d

If we go downwards, the sign will be positive because cos(0)=1

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A. Vx = 3.63 m/s

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A. x component of velocity, Vx = 3.63 m/s

B. y component of velocity, Vy = -11.46t

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C. Magnitude of velocity, |V| = √[(-45.73)² + 3.63²]

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Put the following events in the order they occurred to lead to the formation of the solar system:
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Third → First → Second → Fourth

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A 65 kg person jumps from a window to a fire net 18 m below, which stretches the net 1.1 m. Assume the net behaves as a simple s
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0.03167 m

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The potential energy and the kinetic energy of the system is conserved

P_i=P_f+K_s\\\Rightarrow mgh_i=-mgx+\frac{1}{2}kx^2\\\Rightarrow k=2mg\frac{h_i+x}{x^2}\\\Rightarrow k=2\times 65\times 9.81\frac{18+1.1}{1.1^2}\\\Rightarrow k=20130.76\ N/m

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x=\frac{-\left(-\frac{200}{3157}\right)+\sqrt{\left(-\frac{200}{3157}\right)^2-4\cdot \:1\left(-\frac{1000}{451}\right)}}{2\cdot \:1}, \frac{-\left(-\frac{200}{3157}\right)-\sqrt{\left(-\frac{200}{3157}\right)^2-4\cdot \:1\left(-\frac{1000}{451}\right)}}{2\cdot \:1}\\\Rightarrow x=1.52, -1.45

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