The maximum velocity in a banked road, ignoring friction, is given by;
v = Sqrt (Rg tan ∅), where R = Radius of the curved road = 2*1000/2 = 1000 m, g = gravitational acceleration = 9.81 m/s^2, ∅ = Angle of bank.
Substituting;
30 m/s = Sqrt (1000*9.81*tan∅)
30^2 = 1000*9.81*tan∅
tan ∅ = (30^2)/(1000*9.81) = 0.0917
∅ = tan^-1(0.0917) = 5.24°
Therefore, the road has been banked at 5.24°.
Answer:
The inductor contains
loops
Explanation:
From the question we are told that
The capacitance of the capacitor is 
The resonance frequency is 
The diameter is 
The of the air-core inductor is 
The permeability of free space is 
Generally the inductance of this air-core inductor is mathematically represented as

This inductance can also be mathematically represented as

Where
is the angular speed mathematically given as

So

Now equating the both formulas for inductance

making N the subject of the formula


Substituting value
loops
Answer:
D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole
Explanation:
D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because
1) opposite poles attract each other
2) similar poles repel each other
3)magnetic lines of force start at the north pole and end at the south pole
Answer:
B . unequal heating of the Earth's surface by the sun