Ask question

Ask question

All categories

3 years ago

8

You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel

ocity. In both cases the momentum is the same. Which one would be easier to catch/stop. Explain why.

1 answer:

Lerok [7]3 years ago

7 0

Answer: I would say the object with the Lower velocity because Lighter with Higher velocity makes it heavy, velocity is how heavy something is so the lighter it is the less difficult it will be to catch.

You might be interested in

PLEASE ANSWER QUICK GIVING BRAINLIEST TO THE ONE WHO ANSWERS

dedylja [7]

Answer: Iron combines with oxygen to produce rust, which is the compound named iron oxide.

Explanation: Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron(III) oxide, which we see as rust.

Hope This Helps :)

4 0

3 years ago

Read 2 more answers

9966 [12]

Answer: de?

Explanation:

7 0

3 years ago

A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on th

Serhud [2]

The initial momentum of the yellow and the orange train is 1000kgm/s.

Momentum is the product of the mass and velocity of any object.

Momentum is denoted by P.

Momentum P = mv , where m = mass and v = velocity.

<h3>Given:</h3>

Mass of the orange train = 200kg

Velocity of the orange train = 1m/s

So, the momentum of the orange train will be,

∴ P = mv

P = 200 x 1

P = 200 kgm/s

∴ The initial momentum of the orange train is 200kgm/s.

Mass of the yellow train = 100kg

Velocity of the yellow train = 8m/s

So, the momentum of the yellow train will be,

∴ P = mv

P = 100 x 8

P = 800 kgm/s

∴ The initial momentum of the yellow train is 800kgm/s.

Therefore, the initial momentum of the yellow and the orange train is 1000kgm/s.

Learn more about momentum here:

brainly.com/question/25849204

#SPJ1

5 0

2 years ago

50 Points | Earth & Space Science

babymother [125]

When a product fails to perform as warranted, this is called a) contractual liability. O b) product malfunction. c) malicious manufacture. d) breach of warranty

4 0

3 years ago

A circular copper wire is put in tension under a weight of 7000N. What is the ratio of its diameter after and before the load is

zaharov [31]

Answer:

$\frac{d_f}{d} =0.9999983$

Explanation:

Given:

force applied on the copper wire, $F=7000\ N$

cross sectional area of the wire, $a=0.01\ m^2$

Poisson's ratio, $\mu=0.3$

we have, Young's modulus, $E=128\times 10^3\ MPa$

<u>Stress induced due to the applied force:</u>

$\sigma=\frac{F}{a}$

$\sigma=\frac{7000}{0.01}$

$\sigma=700000\ Pa=0.7\ MPa$

<u>Now the longitudinal strain:</u>

<u /> $\epsilon=\frac{\sigma}{E}$ <u />

<u /> $\epsilon=\frac{0.7}{128\times 10^3}$ <u />

<u /> $\epsilon=5.468\times 10^{-6}$ <u />

Now from the relation of Poisson's ratio:

$\mu=\frac{\nu}{\epsilon}$

where:

$\nu=$ lateral strain

$0.3=\frac{\nu}{5.468\times 10^{-6}}$

$\nu=1.6406\times 10^{-6}$ ..................(1)

<u>Now we find the diameter of the wire:</u>

$a=\pi.\frac{d^2}{4}$

$0.01=\pi\times \frac{d^2}{4}$

$\frac{0.04}{\pi} =d^2$

$d=0.1128\ m=112.8\ mm$

<u>When the tensile load is applied its diameter decreases:</u>

The lateral strain is also given as,

$\nu=\frac{\Delta d}{d}$

$1.6406\times 10^{-6}=\frac{\Delta d}{112.8}$

$\Delta d=0.000185\ mm$

Now the final diameter will be:

$d_f=d-\Delta d$

$d_f=112.8-0.000185$

$d_f=112.799815\ mm$

Now the ratio:

$\frac{d_f}{d} =\frac{112.799815}{112.8}$

$\frac{d_f}{d} =0.9999983$

6 0

3 years ago