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3 years ago

I need help quickly pls

Physics

1 answer:

sukhopar [10]3 years ago

4 0

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

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If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee

Alexus [3.1K]

Answer:

457.81 Hz

Explanation:

From the question, it is stated that it is a question under Doppler effect.

As a result, we use this form

fo = (c + vo) / (c - vs) × fs

fo = observed frequency by observer =?

c = speed of sound = 332 m/s

vo = velocity of observer relative to source = 45 m/s

vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).

fs = frequency of sound wave by source = 459 Hz

By substituting the the values to the equation, we have

fo = (332 + 45) / (332 - (-46)) × 459

fo = (377/ 332 + 46) × 459

fo = (377/ 378) × 459

fo = 0.9974 × 459

fo = 457.81 Hz

7 0

4 years ago

A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package hits the ground, how high

Lelu [443]

Answer:

The package was released at a height of 1015.296 meters.

Explanation:

The package is dropped at an initial velocity different of zero, decelerated and later accelerated by gravity. Let assume that final height is equal to zero, the final height is given by the following equation of motion:

$y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2}$

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$y$ - Final height, measured in meters.

$y_{o}$ - Initial height, measured in meters.

$t$ - Time, measured in seconds.

$g$ - Gravitational constant, measured in meters per square second.

(Positive sign - Package is moving upward, Negative sign - Package is moving downward)

The initial height is now cleared:

$y_{o} = y - v_{o}\cdot t - \frac{1}{2}\cdot g \cdot t^{2}$

Given that $y = 0\,m$ , $v_{o} = 15\,\frac{m}{s}$ , $g = -9.807\,\frac{m}{s^{2}}$ and $t = 16\,s$ , the final height of the package is:

$y_{o} = 0\,m - \left(15\,\frac{m}{s} \right)\cdot (16\,s) - \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (16\,s)^{2}$

$y_{o} = 1015.296\,m$

The package was released at a height of 1015.296 meters.

7 0

3 years ago

What does the band of stability for atomic nuclei refer to

Irina18 [472]

Explanation:

Band of stability for atomic nuclei refer to a narrow region in the graph of number of neutrons to the number of protons for stable nuclei. It is the band of nuclei stability.

We know that radioactive elements achieve stability be ejecting nucleons( neutrons and protons). The regions( combination of number of neutrons and protons) in which the nucleus is most is called band of stability.

5 0

3 years ago

What type of relationship exists between the length of a wire and the resistance, If all other factors remain the same?

Sergio [31]

Answer: A. Resistance is directly related to length.

Explanation: Resistance is directly proportional to wire length. The longer the wire the greater resistance since there is more space for particles to collide. While resistance is inversely proportional with the cross- sectional area of a wire. The bigger the wire lower resistance.

6 0

3 years ago

Read 2 more answers

Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration

Maru [420]

Given parameters:

Initial velocity = 0m/s

Acceleration = 2.857m/s²

Time = 15.5s

Unknown:

Final speed of the car = ?

Solution:

We use one of the motion equations to solve this problem;

V = U + at

Where V is the final velocity

U is the initial velocity

a is the acceleration

t is the time taken

V = 0 + 2.857 x 15.5 = 44.28m/s

6 0

4 years ago