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amid [387]
3 years ago
11

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

information?
Physics
2 answers:
Vesnalui [34]3 years ago
8 0
The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. the <span>comparison is best supported by this information is that beryllium has a lower atomic radius than Barium</span>
nika2105 [10]3 years ago
8 0
<h3><u>Answer;</u></h3>

The comparison that would be best is;

<em>They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Beryllium (Be) is an element is the periodic table with an atomic number of 4, which means it has 4 protons in the nucleus and also 4 electrons in the energy levels, since the number of protons is equal to the number of electrons.</u></em>
  • Beryllium has an electron configuration of 2: 2, which means it has two valence electrons, and has two energy levels which means<em><u> it occupies period two of the periodic table, and group two of the periodic table.</u></em>
  • Barium (Ba) on the other had, has an atomic number of 56, which means it has 56 protons and 56 electrons. Thus it has an electron configuration of; 2;8;18;18;8;2;  this shows that<u><em> it has 6 energy levels thus occupies period 6 and is in group two since it has two valence electrons. </em></u>
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Work is done on a locked door that remains closed while you try to pull it open. True False.
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Answer:False

Explanation:

Work is being done on a body when it causes displacement of body on the application of force

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When we pull the door by a force it causes zero displacements of the door. So we can say that work done on it is zero.

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3 years ago
A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potentialenergy func
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Answer:

A= 148.92  m/s²

Explanation:

Given that

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Now force in the x-direction

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When x=0.4 m

dU/dx= 12 x 0.4 = 4.8

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Acceleration in x direction ,a = -120 m/s²

In y -direction

F= - dU/dy

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When y = 0.56 m

dU/dy = - 3.75 x 3 x 0.56 x 0.56

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So we can say that force in y -direction

F= 3.52 N

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a'=88.2 m/s²

acceleration in y direction is 88.2 m/s²

The resultant acceleration

A=\sqrt{a^2+a'^2}

A=\sqrt{120^2+88.2^2}

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