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MAXImum [283]
2 years ago
15

Fatty acids are ________ Group of answer choices composed of carbon, hydrogen, and oxygen in a 1:2:1 ratio. composed of carbon,

hydrogen, glycerol, and a phosphate group. composed of hydrocarbon chains and a carboxyl group. composed of four linked rings.
Chemistry
1 answer:
VLD [36.1K]2 years ago
7 0

Fatty acids are composed of hydrocarbon chains and a carboxyl group.

<h3>What are Fatty acids ?</h3>

Fatty acids are the building blocks of the fat in our bodies and in the food we eat.

During digestion, the body breaks down fats into fatty acids, which can then be absorbed into the blood.

Fatty acid molecules are usually joined together in groups of three, forming a molecule called a triglyceride.

Generally, a fatty acid consists of a straight chain of an even number of carbon atoms, with hydrogen atoms along the length of the chain and at one end of the chain and a carboxyl group (―COOH) at the other end.

It is that carboxyl group that makes it an acid (carboxylic acid).

Learn more about Fatty Acids here ;

brainly.com/question/13528495

#SPJ1

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A large company has recently suffered a traumatic workplace shooting. What forensics professional will executives most
olga_2 [115]

Answer:

The answer is forensic sociologist

I just took the exam and it’s rights

3 0
3 years ago
how many moles of a nonvolatile, nonelectrolyte solute are required to lower the freezing point of 1000 grams of water by 5.58
Ivan

Answer:

Explanation:

Using freezing point depression formula,

ΔTemp.f = Kf * b * i

Where,

ΔTemp.f = temp.f(pure solvent) - temp.f(solution)

b = molality

i = van't Hoff factor

Kf = cryoscopic constant

= 1.86°C/m for water

= (0 - (-5.58))/1.86

= 3.00 mol/kg

Assume 1 kg of water(solvent)

= (3.00 x 1)

= 3.00 mol.

5 0
3 years ago
Please help! BRAINLIEST to right answer
Anastasy [175]

Answer:

Hailey the answer is D.

Explanation:

if liquid to solid is exothermic then then the other way around would be endorhermic

5 0
3 years ago
Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt
oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

Cu2++2e−→Cu    E∘=0.340 V    cathode

<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0
3 years ago
A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
Maurinko [17]
<h3>Answer:</h3>

P₂ = 0.67 atm

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Gas Laws</u>

Boyle's Law: P₁V₁ = P₂V₂

  • P₁ is pressure 1
  • V₁ is volume 1
  • P₂ is pressure 2
  • V₂ is volume 2
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

<u>Step 2: Solve</u>

  1. Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)
  2. [Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)
  3. [Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂
  4. [Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>

0.673333 atm ≈ 0.67 atm

4 0
3 years ago
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