Answer:
It means that a feature is dimensioned more than once.
For example, suppose you have a drawing of a rectangle, and the width is dimensioned twice. That's an example of over-dimensioning.
Of course, that's a rather obvious example. Sometimes it's more subtle. Suppose the rectangle has the width and height dimensioned, but also the diagonal. This is also an example of over-dimensioning. If the width and height are dimensioned, then you don't need to dimension the diagonal; that's already fixed by Pythagorean theorem.
Yes unless it is a green arrow. Then you have the right away.
Answer:
1. A.True
2. B.False
3. B.False
4. A.True
5. A.True
6. A.True
7. A.True
8. B.False
9. B.False
10. A.True
11. B.False
12. A.True
13. A.True
14. B.False
15. B.False
16. A.True
Explanation:
Most steels have endurance and fatigue limit about half the Tensile strength. Tensile strength of material is the limit of stress at which material then breaks. The tensile stress in a bolt is calculated through tensile force.
Answer:
The time required is 10.078 hours or 605 min
Explanation:
The formula to apply here is ;
K=(d²-d²₀ )/t
where t is time in hours
d is grain diameter to be achieved after heating in mm
d₀ is the grain diameter before heating in mm
Given
d=5.5 × 10^-2 mm
d₀=2.4 × 10^-2 mm
t₁= 500 min = 500/60 =25/3 hrs
t₂=?
n=2.2
First find K
K=(d²-d²₀ )/t₁
K={ (5.1 × 10^-2 mm)²-(2.4 × 10−2 mm)² }/ 25/3
K=(0.051²-0.024²) ÷25/2
K=0.000243 mm²/h
Re-arrange equation for K ,to get the equation for d as;
d=√(d₀²+ Kt) where now t=t₂
![d=\sqrt{0.024^2+0.000243*t} \\\\0.055=\sqrt{0.024^2+0.000243t} \\\\0.055^2=0.024^2+0.000243t\\\\0.055^2-0.024^2=0.000243t\\\\0.002449=0.000243t\\\\0.002449/0.000243=t\\\\10.078=t\\\\t=605min](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B0.024%5E2%2B0.000243%2At%7D%20%5C%5C%5C%5C0.055%3D%5Csqrt%7B0.024%5E2%2B0.000243t%7D%20%5C%5C%5C%5C0.055%5E2%3D0.024%5E2%2B0.000243t%5C%5C%5C%5C0.055%5E2-0.024%5E2%3D0.000243t%5C%5C%5C%5C0.002449%3D0.000243t%5C%5C%5C%5C0.002449%2F0.000243%3Dt%5C%5C%5C%5C10.078%3Dt%5C%5C%5C%5Ct%3D605min)
Answer:
1141
7.2
Explanation:
The evaporator Temperature T1 = -10°C
h1 = 244.55kj/kg
S1 = 0.93782kj/kg
The enthalpy at second state from given condenser pressure from super heated refrigerant table
P2 = 600
S2 = S1
h2 = 267.19kj/kg
Enthalpy at 3 and 4 from condenser pressure
h3 = h4 = 81.5kj/kg
To get cooling load
QL = m(h1-h4)
M= 7
= 7(244.55-81.5)
= 7(163.05)
= 1141.35kw = 1141KW
COP
= h1-h4/h2 -h1
= 244.55-81.5/267.19-244.55
= 163.05/22.64
= 7.2