L = 5 m, w = 1 m, h = 3 m 15 m3 5 m2 30 m2 9 m3 7.5 m3

"All is strange and vague."

AveGali [126]

Answer:

This is Ohio.

Explanation:

(no dude im dead i live in kentucky XP)

4 0

3 years ago

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If an 85.0 mL container of helium gas at standard pressure is heated from 20.oC to 91oC and the pressure is increased to 2.8 atm

erastovalidia [21]

Answer: V₂ = 37.71mL

Explanation: To determine the new volume of Helium gas, use the Combined Gas Law, which states the following relationship among pressure, volume and temperature:

$\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

where index 1 relates to the initial state of the gas and index 2 to the final state of the gas.

Temperature is in Kelvin, so:

T = °C + 273

For this situation, standard pressure is 1 atm. Temperatures will be:

T₁ = 20 + 273 = 293 K

T₂ = 91 + 273 = 364 K

Solving:

$V_{2}=\frac{T_{2}P_{1}V_{1}}{P_{2}T_{1}}$

$V_{2}=\frac{364*1*85}{2.8*293}$

$V_{2}=\frac{30940}{820.4}$

$V_{2}=$ 37.71

The new volume of He gas is 37.71 mL.

5 0

3 years ago

A 140.0 l weather balloon filled with 5.50 moles of helium has a small leak. if the helium leaks at a rate of 10.0 mmol/hr, what

nataly862011 [7]

Answer : The volume of the balloon after 45.0 hour is 128.5 L

Explanation :

First we have to calculate the moles of helium leaked.

In 1 hour, the number of moles of helium leaked = 10.0 mmol

In 45.0 hour, the number of moles of helium leaked = $\frac{45.0hr]{1hr}\times 10.0=450mmol=0.450mole$

conversion used : 1 mmol = 0.001 mole

Now we have to calculate the number of moles of helium remaining in the balloon.

Moles of helium remaining in the balloon = Total moles of helium - Moles of helium leaked

Moles of helium remaining in the balloon = 5.50 - 0.450 = 5.05 mole

Now we have to calculate the volume of the balloon after 45.0 hour.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

$V\propto n$

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

where,

$V_1$ = initial volume of gas = 140.0 L

$V_2$ = final volume of gas = ?

$n_1$ = initial moles of gas = 5.50 mole

$n_2$ = final moles of gas = 5.05 mole

Now we put all the given values in this formula, we get

$\frac{140.0L}{V_2}=\frac{5.50mole}{5.05mole}$

$V_2=128.5L$

Therefore, the volume of the balloon after 45.0 hour is 128.5 L

6 0

3 years ago

COULD I GET HELP PLEASE

Vitek1552 [10]

I think it is A i am 25 out of 100 percent sure Good luck XD

6 0

4 years ago

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The reaction C4H10 ---> C2H6 + C2H4 has activation energy (Ea) of 450 kJ/mol, and the Ea of the reverse reaction is 250 kJ/mo

liraira [26]

Answer:

ΔH = 200 kJ/mol

Explanation:

Step 1: Data given

activation energy (Ea) is: 450 kJ/mol

activation energy (Ea) of the reverse reaction is 250 kJ/mol

Step 2: The balanced equations

C4H10 ---> C2H6 + C2H4 Ea = 450 kJ/mol

C2H6 + C2H4 ---> C4H10 Ea = 250 kJ/mol

Step 3: Calculate ΔH

Since the reverse reaction has a lower activation energy, this means we need less reaction for the reverse reaction to happen. We can say the reaction absorbs energy, so this is the endothermic reaction.

Ea ( of the forward reaction) = ΔH + Ea (of the reverse reaction)

ΔH = Ea ( of the forward reaction) - Ea (of the reverse reaction)

ΔH = 450 kJ/mol - 250 kJ/mol

ΔH = 200 kJ/mol

Since the reactionis endothermi, ΔH is positive

3 0

3 years ago