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vodka [1.7K]
3 years ago
5

K2SO4(aq) + Ba(NO3)2(aq) → 2KNO3(aq) + BaSO4(s)

Chemistry
2 answers:
umka2103 [35]3 years ago
5 0
That would be BaSO4(s)     ( s  means solid)
jeka943 years ago
4 0

Answer:

BaSO_{4(s)}

Explanation:

The chemical reaction presented above represents a <em>precipitation reaction</em> where interacts two solutions as a reactants and produce two products. When you want to know if the products remain in solution or precipitate as a solid you could concentrate your attention in the states of the different compounds, represented for subscript of letters in a parenthesis.

In the present exercise the potassium nitrate (KNO_{3(aq)} )\\ remains in solution owing to the state are (aq) that means aqueous. Barium sulfate (BaSO_{4(s)}), by contrast, will precipitate out because of its state is (s) that means solid.

In summary, the state of compounds helps recognizing the precipitate in a reaction. For this case, the precipitate is BaSO_{4(s)}.

Rgds!

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In a titration, 4.7 g of an acid (HX) requires 32.6 mL of 0.54 M NaOH(aq) for complete reaction. What is the molar mass of the a
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Explanation : Given,

Mass of an acid (HX) = 4.7 g

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Molarity of NaOH = 0.54 M = 0.54 mole/L

First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

\text{Moles of an acid}=\frac{\text{Mass of an acid}}{\text{Molar mass of an acid}}

Now put all the given values in this formula, we get:

0.017604mole=\frac{4.7g}{\text{Molar mass of an acid}}

\text{Molar mass of an acid}=266.985g/mole

Therefore, the molar mass of an acid is 266.985 g/mole

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Why is RNA chemically unstable?
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Which of the following gases effuses the fastest at a given temperature?
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Answer: -

H₂ will diffuse the fastest.

Explanation: -

According to Graham's Law of Diffusion

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7 0
3 years ago
DUPLICATE
Svet_ta [14]
As in relative abundance , one is take reference
So,
One is taken as 1:
Other is subtracted from it:
(1 - 0.6011)(atomic mass of Ga-71) 

Equation can be written as:
<span>69.723 = (0.6011)(68.9256) + (1-0.6011)x </span>
<span>(1-0.6011) is the percentage abundance of Ga-71 expressed in percentage: </span>

<span>Solving for x </span>
<span>28.2918 = 0.3989 x </span>
<span>x= 70.9246.......</span>
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