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vodka [1.7K]
4 years ago
5

K2SO4(aq) + Ba(NO3)2(aq) → 2KNO3(aq) + BaSO4(s)

Chemistry
2 answers:
umka2103 [35]4 years ago
5 0
That would be BaSO4(s)     ( s  means solid)
jeka944 years ago
4 0

Answer:

BaSO_{4(s)}

Explanation:

The chemical reaction presented above represents a <em>precipitation reaction</em> where interacts two solutions as a reactants and produce two products. When you want to know if the products remain in solution or precipitate as a solid you could concentrate your attention in the states of the different compounds, represented for subscript of letters in a parenthesis.

In the present exercise the potassium nitrate (KNO_{3(aq)} )\\ remains in solution owing to the state are (aq) that means aqueous. Barium sulfate (BaSO_{4(s)}), by contrast, will precipitate out because of its state is (s) that means solid.

In summary, the state of compounds helps recognizing the precipitate in a reaction. For this case, the precipitate is BaSO_{4(s)}.

Rgds!

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aev [14]
The link above is a hacker
8 0
3 years ago
3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,
VARVARA [1.3K]

Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

Q_{Ag}=-Q_{liquid}

That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

Best regards.

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4 years ago
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aleksley [76]

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5 0
4 years ago
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