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olganol [36]
2 years ago
12

What is the total number of protons and electrons in one mole of hydrogen gas?

Chemistry
1 answer:
german2 years ago
4 0
1 proton and-1 electrons and 0 neutron
You might be interested in
Question 2 (1 point) Saved
Diano4ka-milaya [45]

Answer:

False, the electrons are on the outside protons and neutrons are in the center

Explanation:

5 0
3 years ago
Read 2 more answers
A 25.0 ml sample of 0.723 m hclo4 is titrated with a 0.27303 m koh solution. the h3o+ concentration after the addition of 66.2 m
tia_tia [17]
This doesn't need an ICE chart. Both will fully dissociate in water.

Assume HClO4 and KOH reacts with one another. All you need to do is determine how much HClO4 will remain after the reaction. Calculate pH.

Step 1:

write out balanced equation for the reaction

HClO4+KOH ⇔ KClO4 + H2O

the ratio of HClO4 to KOH is going to be 1:1. Each mole of KOH we add will fully react with 1 mole of HClO4

Step 2:

Determining the number of moles present in HClO4 and KOH

Use the molar concentration and the volume for each:
25 mL of 0.723 M HClO4

Covert volume from mL into L:
25 mL * 1L/1000mL = 0.025 L

Remember:

M = moles/L so we have 0.025 L of 0.723 moles/L HClO4

Multiply the volume in L by the molar concentration to get:

0.025L x 0.723mol/L = 0.0181 moles HClO4.

Add 66.2 mL KOH with conc.=0.273M
66.2mL*1L/1000mL = .0662 L
.0662L x 0.273mol/L = 0.0181 moles KOH

Step 3:

Determine how much HClO4 remains after reacting with the KOH.

Since both reactants fully dissociate and are used in a 1:1 ratio, we just subtract the number of moles of KOH from the number of moles of HClO4:

moles HClO4 = 0.0181; moles KOH = 0.0181, so 0.0181-0.0181 = 0

This means all of the HClO4 is used up in the reaction.

If all of the acid is fully reacted with the base, the pH will be neutral = 7.

Determine the H3O+ concentration:

pH = -log[H3O+]; [H3O+] = 10-pH = 10-7

The correct answer is 1.0x10-7.
3 0
3 years ago
Read 2 more answers
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
2 years ago
For the Earth's atmosphere, section number two in the pie graph BEST represents the percentage of A) argon B) oxygen C) nitrogen
larisa86 [58]

-<u><em>Oxygen</em></u>

According to Google these are the percentages of the <em>Earths Atmosphere</em>

<em>1</em> 78% - Nitrogen

<u>2</u> 21% - Oxygen

<em>3</em> 0.9% - Argon

<em>4 </em>0.3 - Carbon Dioxide with very small percentage of other elements.

3 0
3 years ago
What is the correct sequence of coefficients when this equation is balanced? ___cs2(l) + ___o2(g) → ___co2(g) + ___so2(g)?
iris [78.8K]

Answer: the sequence is 1, 3, 1, 2.


Explanation:


1) Given equation: CS₂(l) + O₂(g) → CO₂(g) + SO₂(g)


2) To balance:


i) initially C is balanced: 1 atom in the left side, and 1 atom in the right sides


ii) Add coefficient 2 in front of SO₂ to have 2 atoms in each side.


That leads to: CS₂(l) + O₂(g) → CO₂(g) + 2SO₂(g)


iii) Count the O atoms; there are 2 atoms in the left, and 6 atoms in the right side. So, add a coefficient 3 in front of O₂ (in the left) and you get:


CS₂(l) + 3O₂(g) → CO₂(g) + 2SO₂(g)


4) You can verigy that now the equation is balanced:


C: 1 in the left, and 1 in the right


S: 2 in the left, and 2 in the right


O: 6 in the left, and 6 in the right.


5) So, the sequence is 1, 3, 1, 2.


Remember, when the none coefficient is shown it is because it is 1.

4 0
3 years ago
Read 2 more answers
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