All categories

2 years ago

Which of the following techniques is most appropriate for the recovery of solid KNO3 from an aqueous solution of KNO3?

Chemistry

1 answer:

Oxana [17]2 years ago

3 0

Answer: option E. Evaporation to dryness

Explanation:

You might be interested in

0.000431 L<br><br> Express your answer as an integer.

Molodets [167]

A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

Now, converting 0.000431 L to decimal an integer as:

$0.000431 L = 431\times 10^{-6} L$

Since, $1 L = 10^{6} \mu L$

So, $431\times 10^{-6} L\times \frac{10^{6 \mu L}}{1 L} = 431 \mu L$ .

Hence, the integer value for 0.000431 L is $431 \mu L[$ .

3 0

3 years ago

Anomalous data shows on a graph as a

KiRa [710]

Anomalous data on a graph would show up as say a very high or very low value which does not fit in with the normal values which may be background values.If it was a straight line graph then the anomalous point would plot well above or below the line or if it was a bar graph ie a histogram it would be much higher or lower than the surrounding data. In mineral exploration, anomalies are looked for in say geophysics or geochemistry data values for high or low magnetism or conductivity or high chemical values indicating the presence of valuable minerals at that point.

6 0

3 years ago

I do not understand what to do here

DanielleElmas [232]

Answer:

Just Send Answers to make points

Explanation:

6 0

2 years ago

If 4.0 g of helium gas occupies a volume of 22.4 L at 0 o C and a pressure of 1.0 atm, what volume does 3.0 g of He occupy under

WINSTONCH [101]

Answer:

the volume occupied by 3.0 g of the gas is 16.8 L.

Explanation:

Given;

initial reacting mass of the helium gas, m₁ = 4.0 g

volume occupied by the helium gas, V = 22.4 L

pressure of the gas, P = 1 .0 atm

temperature of the gas, T = 0⁰C = 273 K

atomic mass of helium gas, M = 4.0 g/mol

initial number of moles of the gas is calculated as follows;

$n_1 = \frac{m_1}{M} \\\\n_1 = \frac{4}{4} = 1$

The number of moles of the gas when the reacting mass is 3.0 g;

m₂ = 3.0 g

$n_2 = \frac{m_2}{M} \\\\n_2 = \frac{3}{4} \\\\n_2 = 0.75 \ mol$

The volume of the gas at 0.75 mol is determined using ideal gas law;

PV = nRT

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\since, \ \frac{RT}{P} \ is \ constant,\ then;\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1n_2}{n_1} \\\\V_2 = \frac{22.4 \times 0.75}{1} \\\\V_2 = 16.8 \ L$

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.

4 0

3 years ago

What are the charges on barium and fluorine in barium fluoride? 1 point Captionless Image Barium is +2 and fluorine is -2. Bariu

user100 [1]

Answer: Barium is +2, Fluorine is -1

Explanation:

The charge of barium is +2, and the charge of fluorine is -1. You can determine this from the periodic table groups.

The formula for barium fluoride is thus BaF2.

8 0

2 years ago