What mass of propane is necessary to react with the amount of oxygen in the chemical formula C3H8 + 5O2 → 3CO2 + 4H2O

1 answer:

6 0

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

n(O₂)=1.407 mol
M(C₃H₈)=44.1 g/mol

m(C₃H₈)/M(C₃H₈)=n(O₂)/5

m(C₃H₈)=M(C₃H₈)n(O₂)/5

m(C₃H₈)=44.1*1.407/5=12.410 g

the mass of propane is 12.410 g

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