Answer:
a.The 60 km/HR car
Explanation:
Kinetic Energy: This can be defined as the energy of a body due to motion. The S.I unit of kinetic energy is Joules (J).
It can be expressed mathematically as
Ek = 1/2mv²......................... Equation 1
Where Ek = kinetic energy, m = mass, v = velocity.
(i) A car travelling at 30 km/hr, with a mass of m,
Ek = 1/2(m)(30)²
Ek = 450m J.
(ii) A car travelling at 60 km/hr, with a mass of m/2
Ek = 1/2(m/2)(60)²
Ek = 900m J.
Thus , the car travelling at 60 km/hr at half mass has a greater kinetic energy to the car traveling at 30 km/hr at full mass.
The right option is a.The 60 km/HR car
Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.
Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.
The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.
A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.
Learn more about the convex lens here:
brainly.com/question/12847657
#SPJ4
Answer:
9.66 m/s 15° with +y
2.59 m/s 75° with +y
Explanation:
Momentum is conserved in the y direction.
mu₁ + mu₂ = mv₁ + mv₂
u₁ + u₂ = v₁ + v₂
10 m/s + 0 m/s = v₁ cos 15° + v₂ cos 75°
10 = v₁ cos 15° + v₂ cos 75°
Momentum is conserved in the x direction.
mu₁ + mu₂ = mv₁ + mv₂
u₁ + u₂ = v₁ + v₂
0 m/s + 0 m/s = v₁ sin 15° − v₂ sin 75°
0 = v₁ sin 15° − v₂ sin 75°
v₁ sin 15° = v₂ sin 75°
v₂ = v₁ sin 15° / sin 75°
Substitute.
10 = v₁ cos 15° + (v₁ sin 15° / sin 75°) cos 75°
10 = v₁ cos 15° + v₁ sin 15° / tan 75°
10 = v₁ (cos 15° + sin 15° / tan 75°)
v₁ ≈ 9.66 m/s
v₂ ≈ 2.59 m/s
