An electron in a mercury atom drops

1 answer:

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Since the electron dropped from an energy level i to the ground state by emitting a single photon, this photon has an energy of 1.41 × 10⁻¹⁸ Joules.

<h3>How to calculate the photon energy?</h3>

In order to determine the photon energy of an electron, you should apply Planck-Einstein's equation.

Mathematically, the Planck-Einstein equation can be calculated by using this formula:

E = hf

<u>Where:</u>

h is Planck constant.

f is photon frequency.

In this scenario, this photon has an energy of 1.41 × 10⁻¹⁸ Joules because the electron dropped from an energy level i to the ground state by emitting a single photon.

Read more on photons here: brainly.com/question/9655595

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densk [106]

Answer:

Explanation:

a). Find the graph attached for the motion.

b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,

Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

= 5.4 + 7.8

= 13.2 m