1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PSYCHO15rus [73]
3 years ago
5

Analogue signals transmit information for such things as _____________.

Physics
2 answers:
ivann1987 [24]3 years ago
7 0

Transmission of information in ANY form can be done digitally
or analoguely.

Beginning about 30 years ago, everything slowly started changing
to digital.  Today, all commercial satellite communication, all optical
fiber communication, all internet communication, all computer
communication, all commercial cable communication, all commercial
television, and much of the telephone system, are all digital. 

On your computer ... .pdf,  .jpg, .mp3  etc.  are all digital methods of
moving and storing information.

AM and FM radio are an interesting subject.  They're all still analog.
They could easily be changed to all digital, and it would be a big
improvement, both for the broadcasters and for the listeners. 
BUT ... every AM and FM radio that anybody has now would be
obsolete.   Every single radio would either need to be replaced,
OR you'd need to add a digital decoder to every radio, like we
had to do with our TV sets a few years ago when television
suddenly became all digital.  With AM and FM radios, the decoders
would be bigger, and would cost more, than most of the radios.

And that's why commercial radio broadcasting is still analog.
 
suter [353]3 years ago
6 0
<h3><u>Answer</u>;</h3>

A. AM/FM radio

Analogue signals transmit information for such things as <em><u>AM/FM radio</u></em>.

<h3><u>Explanation</u>;</h3>
  • <em><u>Analogue transmission is a method of transmission that involves conveying voice, data, image, signal or video information using a continuous signal which varies in amplitude, phase, or some other property in proportion to that of the variable.</u></em>
  • <em><u>An analog signal differs from a digital signal in that in a digital signal the continuous quantity is a representation of a sequence of discrete values. Digital signals must have finite set of possible valu</u></em>es.
  • <u><em>Am or FM radi</em></u>o information are transmitted using analogue signals
You might be interested in
Formula for calculating work done in machines ​
Archy [21]

Answer:

force×distance

Explanation:

i think that's the answer and it could also be expressed as m×g×d

7 0
3 years ago
Usain Bolt's world-record 100 m sprint on August 16, 2009, has been analyzed in detail. At the start of the race, the 94.0 kg Bo
kifflom [539]

Answer:

893 Newtons

Explanation:

m = Mass of Usain Bolt = 94 kg

a = Acceleration of Usain Bolt in the first 0.89 seconds = 9.5 m/s²

From Newton's Second law

Force

F=ma

\\\Rightarrow F=94\times 9.5

\\\Rightarrow F=893\ N

The average horizontal force exerted by Bolt against the ground during the first 0.890 s of the race is 893 Newtons

3 0
3 years ago
Can someone please help me with these physics problems? I just don’t even know where to start.
KIM [24]

#1

for the block of mass 5 kg normal force is given as

F_n = mg

F_n = 5*9.8 = 49 N

friction force is given as

F_f = \mu F_n

F_f = 0.1*49 = 4.9 N

Net force is given as

F_{net} = ma

F_{net} = 5*2 = 10 N

now we know that

F_{net} = F_{app} - F_f

10 = F_{app} - 4.9

F_{app} = 14.9 N

#2

Normal force is given as

F_n = mg

F_n = 6*9.8

F_n = 58.8 N

now we know that

F_{net} = F_{app} - F_f

F_{net} = 0

as object moves with constant velocity

F_{app} = F_f = 15 N

now for coefficient of friction we can use

F_f = \mu F_n

15 = \mu * 58.8

\mu = 0.255

#3

net force upwards is given as

F = 1.2 * 10^{-4} N

mass is given as

m = 7 * 10^{-5} kg

now as per newton's law we can say

F = ma

1.2 * 10^{-4} = 7 * 10^{-5} * a

a = 1.71 m/s^2

#4

As we know that when block is sliding on rough surface

part a)

net force = applied force - frictional force

F_{net} = F_{app} - F_f

ma = F_{app} - F_f

5*6 = 40 - F_{f}

F_f = 40 - 30 = 10 N

part b)

for coefficient of friction we can use

F_f = \mu F_n

10 = \mu * F_n

here normal force is given as

F_n = mg = 5*9.8 = 49 N

now we have

\mu = \frac{10}{49} = 0.204

#5

if an object is initially at rest and moves 20 m in 5 s

so we can use kinematics to find out the acceleration

d = v_i*t + \frac{1}{2}at^2

20 = 0 + \frac{1}{2}a(5^2)

a = 1.6 m/s^2

now net force is given as

F_{net} = ma

F_{net} = 10*1.6 = 16 N

#6

an object travelling with speed 25 m/s comes to stop in 1.5 s

so here acceleration of object is given as

a = \frac{v_f - v_i}{t}

a = \frac{0 - 25}{1.5} = -16.67 m/s^2

now the force is gievn as

F = ma

F = 5*16.67 = 83.3 N

3 0
4 years ago
How does a pedometer help people reach their fitness goals
goldfiish [28.3K]

how does a pedometer help people reach their fitness goals?

a. It measures calories burned.  

b. It usually doubles as an MP3 player and keeps people motivated.  

c. They count steps during a workout.  

d. They measure the number of lifts done per exercise.

8 0
3 years ago
Read 2 more answers
. A newly discovered planet has three times the mass and five times the radius of Earth. What is the ratio of the acceleration d
NikAS [45]

Answer:

0.12

Explanation:

The acceleration due to gravity of a planet with mass M and radius R is given as:

g = (G*M) / R²

Where G is gravitational constant.

The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg

The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m

Therefore:

g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²

g(planet) = 1.18 m/s²

Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:

g(planet)/g(earth) = 1.18/9.8 = 0.12

3 0
3 years ago
Other questions:
  • How much heat is needed to raise the temperature of 200 g of lead (c = 0.11 kcal/kg ∙ °c) by 10 c°?
    9·1 answer
  • An object is thrown vertically upward such that it has a speed of 75 m/s when it reaches two thirds of its maximum height above
    8·1 answer
  • One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has
    5·1 answer
  • A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i
    9·1 answer
  • Why are multiple trials important when carrying out an experiment?
    5·1 answer
  • (II) The platter of the hard drive of a computer rotates at 7200 rpm (rpm = revolutions per minute = rev/min). (a) What is the a
    7·1 answer
  • A ball droped from a building. How fast is it traveling after falling 3.55s
    8·1 answer
  • Do you think solar roofs and energy storage batteries will become widespread in the future? Why or why not?
    14·1 answer
  • A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d
    7·1 answer
  • Describe an example of Newton's 2nd Law of Motion (heavier objects need more force than lighter objects to make them move).​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!