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PSYCHO15rus [73]
3 years ago
5

Analogue signals transmit information for such things as _____________.

Physics
2 answers:
ivann1987 [24]3 years ago
7 0

Transmission of information in ANY form can be done digitally
or analoguely.

Beginning about 30 years ago, everything slowly started changing
to digital.  Today, all commercial satellite communication, all optical
fiber communication, all internet communication, all computer
communication, all commercial cable communication, all commercial
television, and much of the telephone system, are all digital. 

On your computer ... .pdf,  .jpg, .mp3  etc.  are all digital methods of
moving and storing information.

AM and FM radio are an interesting subject.  They're all still analog.
They could easily be changed to all digital, and it would be a big
improvement, both for the broadcasters and for the listeners. 
BUT ... every AM and FM radio that anybody has now would be
obsolete.   Every single radio would either need to be replaced,
OR you'd need to add a digital decoder to every radio, like we
had to do with our TV sets a few years ago when television
suddenly became all digital.  With AM and FM radios, the decoders
would be bigger, and would cost more, than most of the radios.

And that's why commercial radio broadcasting is still analog.
 
suter [353]3 years ago
6 0
<h3><u>Answer</u>;</h3>

A. AM/FM radio

Analogue signals transmit information for such things as <em><u>AM/FM radio</u></em>.

<h3><u>Explanation</u>;</h3>
  • <em><u>Analogue transmission is a method of transmission that involves conveying voice, data, image, signal or video information using a continuous signal which varies in amplitude, phase, or some other property in proportion to that of the variable.</u></em>
  • <em><u>An analog signal differs from a digital signal in that in a digital signal the continuous quantity is a representation of a sequence of discrete values. Digital signals must have finite set of possible valu</u></em>es.
  • <u><em>Am or FM radi</em></u>o information are transmitted using analogue signals
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A scientist notices that an oil slick floating on water when viewed from above has many different rainbow colors reflecting off
Semenov [28]

Answer:

Explanation:

In case of oil slick a thin layer of oil is formed on water . This thin layer creates a rainbow of colour . The phenomenon is due to interference of light waves , one reflected from the upper surface of oil and the other reflected from the lower surface of the oil.

For formation of bright colour

2 μ t = ( 2n + 1 ) λ / 2

μ is refractive index of oil ,  t is thickness of oil layer  λ is wave length of light falling on the layer .

given μ = 1.2 ,   λ = 750 x 10⁻⁹   ,

2 x 1.2 t = ( 2n + 1 ) 750 x 10⁻⁹ / 2

For minimum thickness n = 0

2.4 t = 375 x 10⁻⁹

t = 156.25 n m

B ) If the refractive index of layer of medium below oil is less than that of oil , the condition of formation of colour changes

The new condition is

2 μ t = n λ

2  x 1.5 t  = 750 nm ,         n = 1 for minimum wavelength .

t = 250 nm

C ) Light mostly transmitted means dark spot is formed at that point .

For that to be observed from water side , the condition is

2 μ t = ( 2n + 1 ) λ / 2

λ = 4μ t / ( 2n + 1 )

For maximum wavelength n = 0

λ = 4μ t

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3 0
3 years ago
At the equator earth rotates with a velocity of about 465 m/s.
Dafna1 [17]
The given velocity is 465 m/s.

Part a.
465 \,  \frac{m}{s} =(465 \times 10^{-3} \,  \frac{km}{s})*( 3600 \,  \frac{s}{h} ) = 1674 \,  \frac{km}{h}
Answer: 1674 km/h

Part b.
1674  \frac{km}{h} = (1674 \,  \frac{km}{h})*(24 \,  \frac{h}{day}  ) = 40176 \,  \frac{km}{day}
Answer: 40,176 km/day.

 
3 0
3 years ago
Read 2 more answers
Master of physics needed
Delicious77 [7]
Hey JayDilla, I get 1/3.  Here's how:
Kinetic energy due to linear motion is:
E_{linear}= \frac{1}{2}mv^2
where
v=r \omega
giving
E_{linear}= \frac{1}{2}mr^2 \omega ^2

The rotational part requires the moment of inertia of a solid cylinder
I_{cyl} =  \frac{1}{2}mr^2
Then the rotational kinetic energy is
E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2
Adding the two types of energy and factoring out common terms gives
\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part.  Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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