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1 year ago

Select the correct answer.

Chemistry

1 answer:

Pavel [41]1 year ago

8 0

Answer: E. $\text{CH}_{4}+2\text{O}_{2} \longrightarrow \text{CO}_{2}+2\text{H}_{2}\text{O}$

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What happens to the motion of molecules when temperature decreases

Juliette [100K]

Answer:

As the temperature of a solid, liquid or gas increases, the particles move more rapidly.

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3 years ago

Read 2 more answers

Given the following balanced reaction between nitrogen gas and oxygen gas to produce nitrous oxide gas, how many moles of nitrou

den301095 [7]

Answer is: 3,3 mol of <span>nitrous oxide gas is produced in this chemical reaction.
</span>Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
from reaction n(N₂) : n(NO) = 1 : 2.
1,65 mol : n(NO) = 1 : 2.
n(NO) = 3,3 mol.
n - amount of substance.

4 0

3 years ago

When two species A and B form an electron-pair bond and A does not provide its electrons for bonding, the bond present between A

vichka [17]

Answer:

Ionic

Explanation:

If A does not have electron to bond, it just receives one electron from B.

It can´t be covalent because A don´t have any electrons to bond with B.

5 0

2 years ago

How many moles of water as a gas can be formed 2.45 L

Alex17521 [72]

Answer:

0.11mole

Explanation:

Let us assume that the condition is at standard temperature and pressure(STP);

Given parameters:

Volume of water = 2.45L

Unknown:

Number of moles found in this volume of water = ?

Solution;

At STP;

Number of moles = $\frac{volume of gas}{22.4}$

Input the parameters and solve;

Number of moles of water = $\frac{2.45}{22.4}$ = 0.11mole

The number of moles of water found is 0.11mole

4 0

2 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.