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nika2105 [10]
3 years ago
8

Which of the following is true about acids? . A. Acids give foods a bitter taste. . . B. Aqueous solutions of acids conduct elec

tricity. . . C. Acids have a pH value greater than 7. . . D. all of the above .
Chemistry
2 answers:
jek_recluse [69]3 years ago
8 0

Answer : The correct options is, (B) Aqueous solutions of acids conduct electricity.

Explanation :

Acid : It is a substance that has ability of donating proton or hydrogen ion, H^+.

The properties of an acid are :

  • Acids are sour in taste.
  • The texture of an acid solution is sticky.
  • It changes the color of the litmus paper to red.
  • It react with a metal to give compound and hydrogen gas.
  • An aqueous solution of an acid conduct electricity.
  • The pH value of acid is less than 7.

Base : It is a substance that has ability of donating hydroxide ion, OH^-.

The properties of an base are :

  • Base are bitter in taste.
  • The texture of an base solution is slippery.
  • It changes the color of the litmus paper to blue.
  • It does not react with a metal.
  • An aqueous solution of an base also conduct electricity.
  • The pH value of base is greater than 7.

Hence, the correct options is, (B) Aqueous solutions of acids conduct electricity.

rusak2 [61]3 years ago
6 0
Acids are substances that have a rich concentration of the proton H+. Acids are bitter in taste and have a pH less than 7. Substances with pH greater than 7 are basic solutions while that at 7 are called neutral solution. The answer to this problem is A. Acids give foods a bitter taste. 
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A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). What is the emf of this cell under st
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Answer:

0.46 V

Explanation:

The emf for the cell is given by:

Eº cell = Eº oxidation + Eº reduction

From the  given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced  from 0 to negative 2, according to the half cell reactions:

4Fe²⁺  ⇒ Fe³⁺ + 4e⁻           oxidation

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From reference tables for the standard reduction potential, we get

Eº red Fe³⁺ / Fe²⁺   Eºred = 0.77 V  

Eº red O₂ / H₂O      Eºred = 1.23 V

Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction  O₂:

Eº cell =   Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V

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