The solubility of carbon dioxide at 400 kPa at room temperature is ;
( B ) 0.61 CO2/L
<u>Given data </u>
pressure of CO₂ = 400 Kpa = 3.95 atm
Kh of CO₂ = 3.3 * 10⁻² mol/L.atm
<h3>Calculate the solubility of carbon dioxide </h3>
Solubility = pressure * Kh value of CO₂
= 3.95 atm * 3.3 * 10⁻² mol / L.atm
= 0.13 mol/l CO₂
= 0.61 CO₂ / L
Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l CO₂.
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From the options the closest answer is ( B ) 0.61 CO₂ / L
Answer:
2d
Explanation:
2d nije moguće. moguće je samo 3d do 7d. provjeri periodni sustav!
ako ne razumiješ, obrati mi pažnju
Here, as they both are physical things without any magnetic property & density difference, screening would be best.
In short, Your Answer would be Option C
Hope this helps!
Answer:
Answer is given below:
Explanation:
<em>Given Data:</em>
mass = 80kg
acceleration = 4 ms
force = 800N
<em>Find out:</em>
friction = ?
<em>Formula</em><em>:</em>
F-friction = weight - f-net
<em>Solution:</em>
weight = (80)(10)
= 800 N
F-net = ma =(80)(4) = 320N
F-friction = weight - F-net
=800 N - 320N
=480N
<em>Answer</em> :
Friction = 480 N
True it is odorless and it has no color