ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.
<h3>What is P
erchlorate ion?</h3>
This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.
This has 32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.
Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.
Read more about Perchlorate ion here brainly.com/question/16895150
#SPJ1
Answer:
Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.
Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.
Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.
Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.
The atomic orbital and radius increases by gaining electron linearly so even electron numbered atoms are diamagnetic while the odd electron numbered atoms are paramagnetic.
Running through the first 18 elements one can observe that there is an alternative odd number of electrons and an even number proofing that that half of the first 18 elements shows paramagnetism and diamagnetism respectively.
Explanation:
Meiosis has two rounds of genetic and cellular division while Mitosis only has one. There are more complicated answers, so i dont know exactly how much info you need.
Answer: The given question is incomplete. The complete question is:
At a certain temperature the rate of this reaction is second order in
with a rate constant of
. 
Suppose a vessel contains
at a concentration of 0.100 M Calculate how long it takes for the concentration of
to decrease to 0.0240 M. You may assume no other reaction is important. Round your answer to 2 significant digits.
Answer: It takes 0.93 seconds for the concentration
to decrease to 0.0240 M.
Explanation:
Integrated rate law for second order kinetics is given by:
= initial concentration = 0.100 M
a= concentration left after time t = 0.0240 M
k = rate constant = 
t = time taken for decomposition = ?

Thus it takes 0.93 seconds for the concentration
to decrease to 0.0240 M.