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Kobotan [32]
2 years ago
7

Please solve and show steps.

Physics
1 answer:
finlep [7]2 years ago
4 0
I don’t think good luck with finding the answers I need points so I did this sorry.:(
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soaring birds and glider pilots can remain aloft for hours without expending power. Discuss why this is so.
vekshin1

Answer:

Since their wings and body develop the drag. When there is warm air then they expand their wings. Since,soaring birds and glider pilots have no engine, they always maintain their high speed to lift their weight in air for hours without expending power by convection

Explanation:

5 0
3 years ago
A particle moves along the x-axis. It is initially at the position 0.170 m, moving with a velocity of 0.190 m/s and acceleration
sukhopar [10]

Answer:

(a)-0.701m

(b)-0.674m/s

Explanation:

Given a = -0.24,m/s² Xo = 0.170m, u = 0.190m/s

X = Xo + ut +1/2at²

X = 0.170 + 0.190×3.6 + 1/2×(-0.24) 3.6² = -0.701m

(b) its velocity at the end of this time interval is v

v = u + at

= 0.190 + (-0.24)× 3.6 = -0.674m/s

7 0
4 years ago
Two students push on a 5-kg cart from opposite sides
sweet-ann [11.9K]

Answer:

nothing will happen the cart will be broken or as it is

4 0
3 years ago
Read 2 more answers
Complete the table.
murzikaleks [220]

Answer:

Write in the correct units that correspond with the letters in the table. 2 ... b = liter. c = pound. Explanation: Goodbye. Smenevacuundacy and 18 .

Explanation:

7 0
3 years ago
Read 2 more answers
One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th
Vlada [557]

For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

F\times L = mg \times \frac{L}{2}

here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

mg = 145 N

now we will have

F = \frac{mg}{2}

F = \frac{145}{2} = 72.5 N

so our applied force is 72.5 N

7 0
4 years ago
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