Answer:
The heat capacity for the second process is 15 J/K.
Explanation:
Given that,
Work = 100 J
Change temperature = 5 k
For adiabatic process,
The heat energy always same.


We need to calculate the number of moles and specific heat
Using formula of heat


Put the value into the formula


We need to calculate the heat
Using formula of heat

Put the value into the formula


We need to calculate the heat capacity for the second process
Using formula of heat

Put the value into the formula



Hence, The heat capacity for the second process is 15 J/K.
All of them have the same potential energy <span />
Answer:
distance between object and image = 18.9 cm
Explanation:
given data
radius of curvature = 18 cm
focal length = 1/2 radius of curvature
magnification = 40%
to find out
distance between object and image
solution
we know lens formula that is
1/f = 1/v + 1/u ....................1
here f = 18 /2 and v and u is object and image distance
and we know m = 40% = 0.40
so 0.40 = -v / u
so here v = - 0.40 u
so from equation 1
1/f = 1/v + 1/u
2/18 = - 1/0.40u + 1/u
u = -13.5 cm ..................2
and
v = -0.40 (- 13.5)
v = 5.4 cm ......................3
so from equation 2 and 3
distance between object and image = 5.4 + 13.5
distance between object and image = 18.9 cm
gawaingnpang nkabuhayan, hamon at oportinidad
Answer:
the ans will be because it has 1.672