Barium nitrate and methane (CH4) are both soluble. They both will dissolve in water, however, barium nitrate will dissociate becoming barium 2+ ions and nitrate becoming NO3 1- ions. All nitrates are soluble and dissociate. CH4 is a weak base and does dissolves but doesn't dissociate. So in solubility terms.... they are both equally soluble just one happens to dissociate into its cations and anions. Hope this helps!
Answer:
2.61 g of NO will be formed
The limiting reagent is the O₂
Explanation:
The reaction is:
4NH₃ + 5O₂ → 4NO + 6H₂O
We convert the mass of the reactants to moles:
3.25g / 17 g/mol = 0.191 moles of NH₃
3.50g / 32 g/mol =0.109 moles of O₂
Let's determine the limiting reactant by stoichiometry:
4 moles of ammonia react with 5 moles of oxygen
Then, 0.191 moles of ammonia will react with (0.191 . 5) / 4 = 0.238 moles of oxygen. We only have 0.109 moles of O₂ and we need 0.238, so as the oxygen is not enough, this is the limiting reagent
Ratio with NO is 5:4
5 moles of oxygen produce 4 moles of NO
0.109 moles will produce (0.109 . 4)/ 5 = 0.0872 moles of NO
We convert the moles to mass, to get the answer
0.0872 mol . 30g / 1 mol = 2.61 g
A model that places earth in the center and has the sun, planets, and other objects orbiting the earth.
Explanation:
The geocentric model is a model that places earth in the center and has the sun, planets and other objects orbiting the earth.
- Based on the geocentric model of the earth, other planetary bodies revolves round the earth.
- The heliocentric model is a stark contrast of the geocentric model.
- In the heliocentric model, the sun is at the center of the solar system.
- This model is now known to be correct.
Learn more:
Sun brainly.com/question/2887352
#learnwithBrainly
Volume = mass/density
Lead: v=5.0g/11.34g/cc = 0.440cc
For lead, the new volume level of water will be 367+0.440= 367.440ml
Iron: v=3.2g/7.874g/cc = 0.406cc
For Iron, the new volume level of water will be 367+0.406= 367.406ml
If you add both, then it will be 367+0.406+0.440= 367.846 mL
First find the volume of each sample and then add that to 367ml of water.
I hope that helps.
