All categories

3 years ago

When monovalent cation (X) binds to divalent anion (Y) it will form

Chemistry

1 answer:

Romashka-Z-Leto [24]3 years ago

8 0

When a monovalent cation X binds to a divalent anion Y, a compound with the formula $X_2Y$ would be formed.

A monovalent cation is an atom that has lost an electron. Hence, such cation has a single positive charge. A monovalent cation X will, thus, be $X^+$

A divalent anion is an atom that has gained two electrons. Such anion has 2 negative charge. Thus, divalent Y would be $Y^2^-$

Since Y is a divalent anion, it requires 2 electrons in order to successfully bind with another charged atom, a cation to be specific. Thus, two of $X^+$ would be required to successfully bind $Y^2^-$

$Y^2^-$ + $X^+$ + $X^+$ ----> $X_2Y$

More on the chemical formula can be found here: brainly.com/question/16741890

You might be interested in

While ALL the information in a Schumer Box is important, which items do you think matter most on a day-to-day basis?

Oksana_A [137]

Answer:

The most important information is: financial charges, annual fees, minimum payments and how the balance is calculated.

Explanation:

A Schumer Box is a table where the credit card companies disclose all the terms and conditions necessary to make a contract with them, as well as disclose all fees, charges, balances and elements that make up the credit card.

All information shown on a Schumer Box is important, but the most important is that which deals directly with the customer's money or balance. This information is: financial charges, annual fees, minimum payments and how the balance is calculated.

3 0

3 years ago

How many liters of 0.615 M NaOH will be needed to raise the pH of 0.385 L of 5.13 M sulfurous acid (H2SO3) to a pH of 6.247?

givi [52]

Answer:

Volume of NaOH required = 3.61 L

Explanation:

H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:

$H2SO3\leftrightarrow H^{+}+HSO3^{-}$ --------(1)

where, Ka1 = 1.5 x 10–2 or pKa1 = 1.824

$HSO3^{-}\leftrightarrow H^{+}+SO3^{2-}$ --------(2)

where, Ka2 = 1.0 x 10–7 or pKa2 = 7.000

The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.

Step 1:

Based on equation(1), at the first eq point:

moles of H2SO3 = moles of NaOH

$i.e. \ 5.13\ moles/L*0.385L = moles\ NaOH\\therefore, \ moles\ NaOH = 1.98\ moles\\V(NaOH)\ required = \frac{1.98\ moles}{0.615\ moles/L} =3.22L$

Step 2:

For the second equivalence point setup an ICE table:

$HSO3^{-}+OH^{-}\leftrightarrow H2O+SO3^{2-}$

Initial 1.98 ? 0

Change -x -x x

Equil 1.98-x ?-x x

Here, ?-x =0 i.e. amount of OH- = x

Based on the Henderson buffer equation:

$pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles$

Volume of NaOH required is:

$\frac{0.634\ moles}{0.615 moles/L}=0.389L$

Step 3:

Total volume of NaOH required = 3.22+0.389 =3.61 L

3 0

3 years ago

The state of matter in which a material has definite shape and definite<br> volume is the

goldenfox [79]

Answer:

It's a solid.

Explanation:

Solids never change their shape as opposed to gases and liquids. This is because their molecules are tightly packed together. Since all solids have a definite shape, it's volume will also be definite.

7 0

3 years ago

a gas container in a thick walled balloon. when the pressure changes from __kPa to 114kpa, the volume changes from 0.654L to 1.3

Hunter-Best [27]

<span>To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:</span>

P1V1/T1 = P2V2/T2

P1 = P2V2T1/T2V1

P1 = (114)(1.32)(596)/(715)(.654)

P1 = 191.80 kPa

4 0

3 years ago

Use the equation:

nadezda [96]

Answer:

37.5 moles of O2 needed

Explanation:

2 moles of C6H6 need 15 moles of O2

5/2 * 15 = 37.5 of O2 needed

8 0

2 years ago