You hear that a storm is moving 15km/HR north. You have been given the storm's_____

student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir

k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

$Q_1 = W + Q_2$

here we know that

$Q_1 = 300 J$

$Q_2 = 50 J$

now we have

$W = 300 - 50$

$W = 250 J$

so work done by the engine is 250 J

now we have

$W = mgh$

$250 = 1.5 \times 9.81 \times h$

$h = 17 m$

4 0

3 years ago

A 2-kg toy car accelerates from 5 to 10 m/s.

andre [41]

<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is $5\frac {kgm} {s^2}$ .

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration = $\frac52 m/s^2$ = $2.5 m/s^2$

The force is defined as the product of mass and acceleration of the body.

Mass of body = 2 kg.

So, force applied = $2 \times 2.5 kgm/s^2$ . = $5kgm/s^2$ .

4 0

3 years ago

A sailor in a small sailboat encounters shifting winds. She sails 2.00 km east, then 3.50 km southeast, and then an additional d

Law Incorporation [45]

Answer:

Third displacement = 2.81 m which is 61.70° north of east.

Explanation:

Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

She sails 2 km east, displacement = 2 i

Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis

Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j

Let third displacement be x i + y j

We have final displacement = 5.80 km east = 5.80 i

From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j

= (4.47+x) i + (y - 2.47) j

Comparing both , we have 4.47+x = 5.80

x = 1.33

y-2.47=0

y = 2.47 j

So third displacement = 1.33 i + 2.47 j

Magnitude of third displacement = $\sqrt{1.33^2+2.47^2} =2.81m$

θ = tan⁻¹(2.47/1.33) = 61.70°

So third displacement = 2.81 m which is 61.70° north of east.

7 0

3 years ago

German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (

timama [110]

According to the information given, the Heisenberg uncertainty principle would be given by the relationship

$\Delta x \Delta v \geq \frac{h}{4\pi m}$

Here,

h = Planck's constant

$\Delta v$ = Uncertainty in velocity of object

$\Delta x$ = Uncertainty in position of object

m = Mass of object

Rearranging to find the position

$\Delta x \geq \frac{h}{4\pi m\Delta v}$

Replacing with our values we have,

$\Delta x \geq \frac{6.625*10^{-34}m^2\cdot kg/s}{4\pi (9.1*10^{-31}kg)(0.01*10^6m/s)}$

$\Delta x \geq 5.79*10^{-9}m$

Therefore the uncertainty in position of electron is $5.79*10^{-9}m$

8 0

3 years ago

Which statement best describes the difference between ultraviolet light and infrared light

lys-0071 [83]

The infrared<span> (</span>IR<span>) and the </span>ultraviolet(UV<span>) represent the two extremities of the visible spectrum (400-700nm). While </span>IR<span> represents electromagnetic radiation
with wavelengths longer than those of visible </span>light<span>, </span>UV<span> represents wavelengths
shorter than visible </span>light<span>.
</span><span>
</span>

6 0

3 years ago

You hear that a storm is moving 15km/HR north. You have been given the storm's______