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4 years ago

13

You hear that a storm is moving 15km/HR north. You have been given the storm's______

1 answer:

Elodia [21]4 years ago

7 0

You have been given the storm's velocity.

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A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t

Fittoniya [83]

Answer: $10.82 kg-m^2$

Explanation:

Given

Mass of solid uniform disk $M=13 kg$

radius of disk $r=1.25 m$

mass of lump $m=1.7 kg$

distance of lump from axis $r_0=0.63$

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk $I_1=\frac{Mr^2}{2}$

$I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2$

Final moment of inertia $I_f$ =Moment of inertia of disk+moment of inertia of lump about axis

$I_f=\frac{Mr^2}{2}+mr_0^2$

$I_f=10.15+1.7\times 0.63^2$

$I_f=10.15+0.674$

$I_f=10.82 kg-m^2$

3 0

4 years ago

Please select the word from the list that best fits the definition Visualizes where items are located

Amanda [17]

Answer:I’m pretty sure it’s spatial

Explanation:

3 0

4 years ago

Read 2 more answers

An exoplanet is in an elliptical orbit around a distant star. At its closest approach, the exoplanet is 0.540 AU from the star a

atroni [7]

Answer:

0.71121 km/s

Explanation:

$v_1$ = Velocity of planet initially = 54 km/s

$r_1$ = Distance from star = 0.54 AU

$v_2$ = Final velocity of planet

$r_2$ = Final distance from star = 41 AU

As the angular momentum of the system is conserved

$mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s$

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

7 0

3 years ago

What is heredity? i think its physics

Rashid [163]

It's the passing of traits/characteristics from the parent(s) to the offspring(kids).<span>This is how offspring cells become predisposed to the genes/traits of the parent cells</span>.

8 0

3 years ago

A typical adult human lung contains about 330 million tiny cavities called alveoli. Estimate the average diameter of a single al

Amanda [17]

Answer:

The average diameter of a single alveolus is 0.0222 cm.

Explanation:

Volume of the lung ,V= 1.9 L

$1 L = 1000 cm^3$

$1.9 L=1.9\times 1000 cm^3=1900 cm^3$

Number of alveoli in a human lung = $330\times 10^6$

Volume of single alveoli =v

$v\times 330\times 10^6=V$

$v=\frac{1900 cm^3}{330\times 10^6}$

$v=5.7575\times 10^{-6} cm^3$

The alveoli are spherical.

Radius of an alveolus = r

Volume of the sphere = $\frac{4}{3}\pi r^3$

$v=\frac{4}{3}\pi r^3$

$5.7575\times 10^{-6} cm^3=\frac{4}{3}\times 3.14\times r^3$

$r=0.0111 cm$

Diameter of the alveolus =d

d = 2r = 2 × 0.0111 cm = 0.0222 cm

The average diameter of a single alveolus is 0.0222 cm.

7 0

3 years ago