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3 years ago

The image shows a pendulum in simple harmonic motion. The pendulum starts at A and swings to E.

Physics

2 answers:

Genrish500 [490]3 years ago

7 0

D: Velocity is decreasing. Acceleration is increasing.

A: Velocity is zero.

Flauer [41]3 years ago

4 0

The pendulum starts from rest at A, hence the velocity of pendulum at A is zero.

So velocity is zero at A

As the pendulum swings from A to E, it first gains speed from A to C and the speed decreases from C to E coming to a momentary stop at E.

Similarly, as the pendulum swings from A to E, the acceleration first decreases A to C (becoming zero at C) and the acceleration increases from C to E coming to a maximum at E.

D: Velocity is decreasing. Acceleration is increasing.

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3 years ago

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A truck drives with a constant linear speed v_iv i v, start subscript, i, end subscript down a road with two curves. The first

Alex

Answer:

Explanation:

Centripetal acceleration is given by

$a = \dfrac{v^2}{r}$

where v is the linear velocity and r is the radius of the curve.

Let the centripetal acceleration on the curve of radius R be $a_1$ .

Then

$a_1 = \dfrac{v_i^2}{R}$

Let the centripetal acceleration on the curve of radius 3R be $a_2$ .

Then

$a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1$

Here, we see that the acceleration decreases by a factor of 3.

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3 years ago

The ________ is the maximum value or strength of the signal over time; typically this value is measured in volts.

Harrizon [31]

Peak value is what we say to the maximum value of the signal..

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3 years ago

6. A person lifts a package weighing 75 N. If she lifts it 1.2 m off the floor,

balandron [24]

Answer:

90 Joules

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75×1.2=90.

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3 years ago

A parachutist's fall to Earth is determined by two opposing forces. A gravitational force of 605 N acts on the parachutist. Afte

Doss [256]

Answer:15.8 m/s

Explanation:

Given

Gravitational Force $F_g=605 N$

Air resistance $F_d=689 N$

mass of Parachutist $=\frac{605}{9.8}=61.73 kg$

Velocity after $3 s$

$v=u+at$

$v=0+9.8\times 3$

$v=29.4 m/s$

Now Parachutist opens the parachute

Net for on Parachutist

$605-689=-84$

$84 N$ drag force

therefore deceleration $\frac{84}{61.73}=1.36 m/s^2$

velocity after 10 s is

$v_1=v+at$

$v_1=29.4-1.36\times 10$

$v_1=15.8 m/s$

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4 years ago