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Vera_Pavlovna [14]
2 years ago
13

Determine the hybrid orbital of this molecule.

Chemistry
1 answer:
Pavel [41]2 years ago
7 0

The hybrid orbital of this molecule is sp^3. Hence, option C is correct.

<h3>What is hybridisation?</h3>

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

In this compound, sp^3 a hybrid orbital makes I-O bonds. Due to sp^3hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of IO^{3-} the ion is pyramidal.

The hybrid orbital of this molecule is sp^3. Hence, option C is correct.

Learn more about hybridisation here:

brainly.com/question/23038117

#SPJ1

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The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?
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Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

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Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

Therefore, the volume of pure diamond is 0.493inch^3

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