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Vera_Pavlovna [14]
2 years ago
13

Determine the hybrid orbital of this molecule.

Chemistry
1 answer:
Pavel [41]2 years ago
7 0

The hybrid orbital of this molecule is sp^3. Hence, option C is correct.

<h3>What is hybridisation?</h3>

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

In this compound, sp^3 a hybrid orbital makes I-O bonds. Due to sp^3hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of IO^{3-} the ion is pyramidal.

The hybrid orbital of this molecule is sp^3. Hence, option C is correct.

Learn more about hybridisation here:

brainly.com/question/23038117

#SPJ1

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Standard reduction potentials are based on which element?
KonstantinChe [14]
They're based on hydrogen.
6 0
2 years ago
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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam
MAXImum [283]

Explanation:

The given data is as follows.

       Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence,   moles of NaOH in 97 ml = \frac{0.1090 \times 97}{1000}

                                                       = 10.573 \times 10^{-3} mol

Moles of HCl in 21.00 ml = \frac{0.2060 \times 21}{1000}

                                         = 4.326 \times 10^{-3} mol

Therefore, total moles of NaOH that reacted are as follows.

           10.573 \times 10^{-3} mol - 4.326 \times 10^{-3} mol      

                = 6.247 \times 10^{-3} mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

                  \frac{6.247 \times 10^{-3}}{3}

                    = 2.082 \times 10^{-3} mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

                    2.082 \times 10^{-3} mol \times 40 g/mol

                         = 83.293 \times 10^{-3} g

                         = 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore,       40 g NaOH = 122 g benzoic acid

So,            0.0832 g NaOH = \frac{122 g}{40 g} \times 0.0832 g

                                             = 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

                      \frac{0.253 g}{0.3471 g} \times 100

                           = 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0
3 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
2 years ago
Will chlorine gas effuse more quickly than ammonia gas
beks73 [17]
This statement is false due to the fact that the ammonia gas has the lower molar mass.
6 0
3 years ago
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A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a
Tems11 [23]
No, according to physics no work has been done.

Work must have been done by muscular force but in terms of physics no work has been done.

In physics,work is said to be done only if the force applied produced some kind of displacement in the direction of force.

In this example provided, no work has been done since the boulder doesn't get displaced,it continues to remain at its original position.

Hope This Helps You!
6 0
3 years ago
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