Osmium has a density of 22.6 g/cm^3. What volume (in cm^3) would be occupied by a 21.8 g sample of osmium?
1 answer:
0.9645 cm³ is the occupied volume by a 21.8 g sample of osmium of density of 22.6 g/cm^3.
Given values are:
- Mass, m = 21.8 g
- Density, d = 22.6 g
Density is given by,
⇒
⇒
⇒
∴The volume is 0.9645cm^3
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Answer:
<h2>6.64 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>6.64 moles</h3>Hope this helps you
<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ
<u>Explanation:</u>
To calculate the mass of water, we use the equation:
Density of water = 1 g/mL
Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
To calculate the heat absorbed by the water, we use the equation:
where,
q = heat absorbed
m = mass of water = 1500 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature =
Putting values in above equation, we get:
Hence, the amount of heat required to warm given amount of water is 470.9 kJ