The motivation to abstain from adding water to concentrated acids is that, with a few acids, amid weakening, a considerable measure of warmth is discharged, by adding the corrosive to the water, the generally extensive measure of water will retain the warmth. On the off chance that you added water to concentrated corrosive when you initially beginning pouring the water, it could get sufficiently hot for the little measure of water that was filled all of a sudden bubble and splatter corrosive on you. Concentrated sulfuric corrosive is most famous for doing this, not all acids get that hot on weakening, but rather in the event that you make a propensity for continually adding the corrosive to water for every one of them, you can't turn out badly.
Answer:
16.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of He = 0.750 mole
Volume of He =?
Recall:
1 mole of any gas occupy 22.4 L at STP. This also implies that 1 mole of He occupies 22.4 L at STP.
Finally, we shall determine the volume occupied by 0.750 mole of He. This can be obtained as follow:
1 mole of He occupied 22.4 L at STP.
Therefore, 0.750 mole of He will occupy = 0.750 × 22.4 = 16.8 L at STP.
Thus, 0.750 mole of He is equivalent to 16.8 L
The correct answer among the choices given is option D. Benzene is the simplest aromatic compound. It is the basic unit or part of an aromatic compound. It has a configuration of six carbon atoms. Aromatic compounds can be monocyclic consisting of only one benzene or polycylclic consisting of many benzene rings.
Answer:
Mass = 824.57 g
Explanation:
Given data:
Mass of bromine = ?
Number of moles of bromine = 5.16 mol
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of bromine = 159.8 g/mol
by putting values,
Mass = 5.16 mol × 159.8 g/mol
Mass = 824.57 g
