All categories

2 years ago

Water is to a river as ____________ is to a wire

Physics

2 answers:

irga5000 [103]2 years ago

4 0

Answer:

electricity

Explanation:

mylen [45]2 years ago

3 0

Answer:current

Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)

You might be interested in

What is the frequency of a wave whose wavelength is 0.7m and whose velocity is 120m/s?

ANEK [815]

Answer:

f=171.43Hz

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.

Then replacing with the data of the problem,

f= $\frac{120\frac{m}{s} }{0.7m}$

f=171.43 $\frac{1}{s}$

f=171.43 Hz (because $\frac{1}{s} = Hz$ , 1 hertz equals 1 wave passing a fixed point in 1 second).

5 0

4 years ago

A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?

Vladimir [108]

This question involves the concepts of Newton's Second Law of Motion.

The acceleration of the bowling ball will be "0.67 m/s²".

<h3>Newton's Second Law of Motion</h3>

According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

$F=ma\\\\a=\frac{F}{m}$

where,

a = acceleration = ?
F = Magnitude of the applied force = 6 N
m = Mass of the ball = 9 kg

Therefore,

$a=\frac{6\ N}{9\ kg}$

a = 0.67 m/s²

Learn more about Newton's Second Law of Motion here:

brainly.com/question/13447525

#SPJ1

7 0

3 years ago

A laser beam passes through a diffraction grating and the second order bright spot is porodced at an angle of 22 degress from th

Evgesh-ka [11]

Answer:

The highest order spot is 5.33.

Explanation:

Given that,

Angle = 22°

Order number = 2

In a laser diffraction experiment, the condition for constructive interference or bright spot is

$d\sin\theta=m\lambda$

Put the value into the formula

$d\sin22=2\lambda$

$\dfrac{d}{\lambda}=\dfrac{\sin22}{2}$

$\dfrac{d}{\lambda}=0.1873$

The maximum grating for

$\theta=90^{\circ}$

We need to calculate the highest order spot

Using formula of the highest order spot

$m=\dfrac{d\sin\theta}{\lambda}$

Put the angle into the formula

$m=\dfrac{d}{\lambda}$

Put the value into the formula

$m=\dfrac{1}{0.1873}$

$m=5.33$

Hence,The highest order spot is 5.33.

7 0

4 years ago

a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.

Gwar [14]

Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite direction to the incident ray.

3 0

2 years ago

The electric field of a charge Q at a distance d away is measured as E What will the electric field measure at a distance 1/2 d

Neporo4naja [7]

Answer:

Correct answer: E₁ = 4 · E The electric field increased four times

Explanation:

Given:

E - Electric field at distance d

E₁ - Electric field at distance d₁

Q - Charge of an object

d₁ = (1/2) d

The formula by which the electric field is calculated is:

E = k Q / d²

Electric field at a distance d₁

E₁ = k Q / d₁²

We will form their quotient

E₁ / E = ((k Q) / d₁²) / ((k Q) / d²)

When the constant k and the charge Q is canceled we get:

E₁ / E = (1 / d₁²) / (1 / d²) = d² / d₁² = d² / ((1/2) d)² = 1 /(1/4) = 4

E₁ = 4 · E

The electric field increased four times

God is with you!!!

4 0

4 years ago