Answer:
f=171.43Hz
Explanation:
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.
Then replacing with the data of the problem,
f=
f=171.43
f=171.43 Hz (because
, 1 hertz equals 1 wave passing a fixed point in 1 second).
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
<h3>Newton's Second Law of Motion</h3>
According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

where,
- a = acceleration = ?
- F = Magnitude of the applied force = 6 N
- m = Mass of the ball = 9 kg
Therefore,

a = 0.67 m/s²
Learn more about Newton's Second Law of Motion here:
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Answer:
The highest order spot is 5.33.
Explanation:
Given that,
Angle = 22°
Order number = 2
In a laser diffraction experiment, the condition for constructive interference or bright spot is

Put the value into the formula



The maximum grating for

We need to calculate the highest order spot
Using formula of the highest order spot

Put the angle into the formula

Put the value into the formula


Hence,The highest order spot is 5.33.
Answer:
If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)
The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite direction to the incident ray.
Answer:
Correct answer: E₁ = 4 · E The electric field increased four times
Explanation:
Given:
E - Electric field at distance d
E₁ - Electric field at distance d₁
Q - Charge of an object
d₁ = (1/2) d
The formula by which the electric field is calculated is:
E = k Q / d²
Electric field at a distance d₁
E₁ = k Q / d₁²
We will form their quotient
E₁ / E = ((k Q) / d₁²) / ((k Q) / d²)
When the constant k and the charge Q is canceled we get:
E₁ / E = (1 / d₁²) / (1 / d²) = d² / d₁² = d² / ((1/2) d)² = 1 /(1/4) = 4
E₁ = 4 · E
The electric field increased four times
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