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2 years ago

7

You want to see both Michael and Meet Wally Sparks. If you purchase tickets for both

1 answer:

Aleonysh [2.5K]2 years ago

6 0

$2.

Both tickets cost $1.50
$1.50 x 2 = $3
$5 - $3 = $2

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Following in each of the following three mechanisms, the crank is the input link, 1) draw vectors with labeled angles 2) write t

elena-14-01-66 [18.8K]

<u>Explanation:</u>

1. $\theta_{4}=90^{\circ}, \theta_{1}=\theta^{\circ}$ (diagram)

2.

vector loop equation is

$\overline{R_{1}}+\overline{R_{2}}+\overline{R_{3}}=\overline{R_{4}}\\$

the exponential form,

$r_{1} e^{j \exp (0)}+r_{2} e^{j \theta_{2}}+r_{3} e^{j \theta_{3}}=r_{4} e^{j(90)}$

$e=\cos \theta+j \sin \theta$

3.

Real part, $r_{1}+\ r_{2} \cos \theta_{2}+\ r_{3} \cos \theta_{3}=0$ (i)

Imaginary part, $0+r_{2} \sin \theta_{2}+r_{3} \sin \theta_{3}=r_{4}$ (ii)

From above equation,we get unknown variables,

Now, $\theta_{2}, \theta_{3} \& r_{4}$

If $\theta_{2}$ is given,

From (i), $\theta_{3}=\cos ^{-1}\left(\frac{-r_{1}-r_{2} \cos \theta_{2}}{r_{3}}\right)$

and from (ii), we get

$x_{4}=r_{2} \sin \theta_{2}+r_{3} \sin \left[\cos ^{-1}\left(\frac{-\gamma_{1}-r_{2} \cos \theta_{2}}{r_{3}}\right)\right]$

8 0

4 years ago

1. (15) A truck scale is made of a platform and four compression force sensors, one at each corner of the platform. The sensor i

Elanso [62]

Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, $\epsilon$ = 3%

= 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = $0.03 \times 30 \times 10^9$

$\frac{P}{A} =0.03 \times 30 \times 10^9$

$P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$

= 342119.44 N

For the four sensors,

Maximum weight = 4 x P

= 4 x 342119.44

= 1368477.76 N

Therefore, weight in kg is $m=\frac{W}{g}=\frac{1368477.76}{9.81}$

m = 139498.24 kg

b). Change in resistance

$k=\frac{\Delta R/R}{\Delta L/L}$

$\Delta R = k. \epsilon R$ , since $\epsilon= \Delta L/ L$

$\Delta R = 6.9 \times 0.03 \times 340$

$\Delta R = 70.38$ Ω

For 4 resistance of the sensors,

$\Delta R = 70.38 \times 4 = 281.52$ Ω

c). $k=\frac{\Delta R/R}{\epsilon}$

If linear strain,

$\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$ , where k = 1

$\Delta R = \frac{\Delta L}{L} \times R$

$\Delta R = 0.03 \times 340$

$\Delta R = 10.2$ Ω

4 0

3 years ago

Two common types of glue

dolphi86 [110]

Answer:

white craft glue

yellow wood glue

Explanation:

the answer is this!

was it correct?sir!?

8 0

2 years ago

Read 2 more answers

For a gearbox power and efficiency test apparatus that accommodates interchangeable gearboxes, drive up to 0.5kW. How to select

BigorU [14]

Answer:

First we must know the efficiency of the gearbox in which energy is lost by friction between its components, we divide this efficiency by the nominal power and find the real power.

With this value knowing the speed of rotation of the gearbox we select an engine that has a power just above.

Also keep in mind that the motor torque must be greater than the resistance offered by the gearbox and the 0.5Kw machine

4 0

4 years ago

Fill in the tables and find the equivalent resistance for the following circuits:

Dafna11 [192]

Answer:

12 32

Explanation:

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2 years ago