is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:
First has a natural water content of 25% = = 0.25
Shrinkage limit,
We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
------> eq 1
The above equation is at ,
Applying the given values, we get
Shrinkage limit is lowest water content
Applying the given values, we get
Applying the found values in eq 1, we get
Answer:
A)The sketches for the required planes were drawn in the first attachment.
B)The sketches for the required directions were drawn in the second attachment.
To draw a plane in a simple cubic lattice, you have to follow these instructions:
1- the cube has 3 main directions called "a", "b" and "c" (as shown in the first attachment)
2- The coordinates of that plane are written as: π:(1/a₀ 1/b₀ 1/c₀) (if one of the coordinates is 0, for example (1 1 0), c₀ is ∞, therefore that plane never cross the direction c).
3- Identify the points a₀, b₀, and c₀ at the plane that crosses this main directions and point them in the cubic cell.
4- Join the points.
To draw a direction in a simple cubic lattice, you have to follow these instructions:
1- Identify the points a₀, b₀, and c₀ in the cubic cell.
2- Draw the direction as a vector-like (a₀ b₀ c₀).
