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4 years ago

Is air conditioner a refrigerator?

Engineering

1 answer:

Sergeu [11.5K]4 years ago

8 0

Answer: No, the air conditioner is not a refrigerator

Explanation:

First, We need to make a difference between refrigerant and refrigerator

Refrigerator is a compartment used to kept cool and store the food and drink.

Refrigerant: A substance used for the refrigeration

Refrigeration: It is the process to keep a material cold, generally food and drink

Then: The air conditioner is a refrigerant and the air conditioner unit is a refrigerator

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What steel type and ASTM designation is preferred for W-shapes?

Ulleksa [173]

Answer:

The preferred steel type for W-shapes is structural steel and the its preferred ASTM designation is ASTM A992.

Explanation:

The ASTM A992 is a structural steel and it's the most available for w-shapes; besides its availabilty, its ductility improvements makes it the preferred choice; other common designations for this shapes are ASTM A572 Grade 50,0r ASTM A36, but this designations aren't as available as ASTM A992, and it has to be confirmed prior to their specification.

3 0

4 years ago

A ladder logic program and the associated physical input/output components are given below. Lighting changes from full darkness

Katena32 [7]

Answer:

O2 is true.

Explanation:

8 0

4 years ago

The pump of a water distribution system is powered by a 15-kW electric motor whose efficiency is 90 percent. The water flow rate

wariber [46]

Answer:

Mechanical power of pump is 74.07%.

Explanation:

Power of motor = 15 KW

Efficiency of motor= 90%

So the actual power(P) supplied by motor = 0.9 x 15 KW

P=13.5 KW

Water flow rate = 50 L/s

Volume flow rate = 50 L/s

We know that

$1000\ L/s=1\ m^3/s$

$Volume\ flow \rate =0.05\ m^3/s$

We know that pump is an open system and work input for open system can be calculated as

W=VΔP

ΔP is the pressure difference

V is the volume flow rate

So by putting the values

W=0.05 (300-100) (here ΔP=300 - 100=200 KPa)

W=10 KW

So mechanical power of pump

$\eta =\dfrac{W}{P}$

$\eta =\dfrac{10}{13.5}$

η =0.7407

Mechanical power of pump is 74.07%.

6 0

3 years ago

Using the tables for water determine the specified property data at the indicated state. For H2O at T = 140 °C and v = 0.2 m3/kg

Dennis_Churaev [7]

Answer:

$h = 1429.74\,\frac{kJ}{kg}$

Explanation:

The determination of any further properties requires the knowledge of two independent properties. (Temperature and specific volume in this case). The specific volumes for saturated liquid and vapor at 140 °C are, respectively:

$\nu_{f} = 0.001080\,\frac{m^{3}}{kg}$