Is air conditioner a refrigerator?

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

Trava [24]

Answer:

16

Explanation:

Have a good day my friend

8 0

3 years ago

Read 2 more answers

On December 5, 2017, the Tursis defaulted on their promissory note to the Green Mountain Inn. On June 11, 2017, PP, Inc., former

leva [86]

Answer:

The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.

Explanation:

The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.

5 0

3 years ago

A rectangular concrete (n=0.013) channel 20 feet wide, on a 2.5% slope, is discharging 400 ft3 /sec into a stilling basin. The s

Sonbull [250]

Answer:

Length of stilling basin = 32.9 feet

Height of end sill = 6.58 feet

Explanation:

Discharge = Q = 400 ft^3 /sec

Slope = 2.5 ft

Width = 20 feet

n = 0.013

we will assume the depth of flow as "d"

Q = 1/n (R)^2/3 (slope)^1/2 A ( here R is the hydraulic Radius)

by substituting the given data in above formula we get:

400 = 1/0.013 * (R)^2/3 * sqrt (2.5/100) * 20d

R = A/P

here, A is the flow area and P is the wetted perimeter

400*0.013 = (20d/(20+20d))^2/3 * sqrt(2.5/100) * 20d

d = 1.42 feet

Depth of stilling channel before the jump will be = d1 = 8 feet

Depth of stilling channel after the jump will be = d2 = 1.42 feet

Length of stilling basin = 5(d2 - d1)

= 5( 8 - 1.42)

Length of stilling basin = 32.9 feet

Now calculating the height of end sill:

Jump height = (8 - 1.42)

Height of end sill = 6.58 feet

8 0

3 years ago

Find Tpi, D and angle Tpf = 6.65 d = 3 3/16 LT = 6in

ipn [44]

Answer:

Find Tpi, D and angle

Tpf = 6.65

d = 3 3/16

LT = 6in

3 0

2 years ago

A 280-km-long pipeline connects two pumping stations. If 0.56m3/s are to be pumped through a 0.62-m-diameter line, the discharge

ratelena [41]

Answer:

Explanation:

(a) we take the free surface of the lake to point 1 and the free surfaces of the storage tank to point 2. We also take the lake surface as the reference level (z1= 0), and thus the potential energy at points 1and 2 are pe1= 0 and pe2= gz2. The flow energy at both points is zero since both 1 and 2 are open to the atmosphere (P1= P2= Paytm). Further, the kinetic energy both points is zero (ke1= ke2= 0) since the water at both locations is essentially stationary. The mass flow rate of water and its potential energy at point 2 kg/s70/s)m070.0)(kg/m1000(33===V&&rmkJ/kg196.0/sm1000kJ/kg1m)20)(m/s(9.8122222===gzpe

Then the rate of increase of the mechanical energy of water becomes kW13.7kJ/kg)6kg/s)(0.1970()0()(22inmech,outreach,fluid mech,===-=-=DpempemeemE&&&&The overall efficiency of the combined pump-motor unit is determined from its definition,67.2%or 0.672

NB:

Please check the attached file for clearer work.

4 0

3 years ago