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3 years ago

Write fulk form of FPS?

Physics

1 answer:

zzz [600]3 years ago

4 0

Answer:

<u>Foot per second. Foot-pound-second system. Frames per second, the frequency (rate) at which consecutive images (frames) appear on a display.</u>

Explanation:

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I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation

ludmilkaskok [199]

Answer:

$-5.39\times10^{33} J$

Explanation:

Potential energy =

$-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J$

7 0

2 years ago

Coiling wire around an iron core and applying an electric current through the wire creates a temporary magnet called an electrom

Serggg [28]

Answer:

C) Use a battery with more voltage.

Explanation:

The equation for the magnetic field around a coil is given by,

B = μ₀NI

where,

B = Magnetic flux density

μ₀ = permeability

N = number of turns per meter

I = Current in the wire

So when using a higher voltage battery, more current passes through the battery as resistance of the wire remains the same.

5 0

2 years ago

Read 2 more answers

A Boeing 777 aircraft has a mass of 300,000 kg. At a certain instant during its landing, its speed is 27.0 m/s. If the braking f

GarryVolchara [31]

Answer:

Speed of the airplane 10.0 s later = 12.2 m/s

Explanation:

Mass of Boeing 777 aircraft = 300,000 kg

Braking force = 445,000 N

Deceleration

$a=\frac{445000}{300000}=1.48m/s^2$

Initial velocity, u = 27 m/s

Time , t = 10 s

We have equation of motion, v =u +at

v = 27 + (-1.48) x 10 = 27 - 14.8 = 12.2 m/s

Speed of the airplane 10.0 s later = 12.2 m/s

6 0

3 years ago

Three monkeys A, B, and C weighing 20, 26, and 25 lb, respectively, are climbing up and down the rope suspended from D. At the i

Marina86 [1]

Answer: $2235.2lb-ft/s^2$

Explanation:

Given

Mass of monkey A=20lb

Mass of monkey B=26lb

Mass of monkey C=25lb

acceleration of monkey A= $4.2ft/s^2$

acceleration of monkey B=0

acceleration of monkey C= $-5.4ft/s^2$

Force Due to monkey A $\left ( F_A\right )=20\times 4.2 =84lb-ft/s^2\left ( downwards\right )$

Force Due to monkey A $\left ( F_B\right )=26\times 0 =0lb-ft/s^2$

Force Due to monkey A $\left ( F_C\right )=25\times 5.4 =135 lb-ft/s^2\left ( upward\right )$

In addition to it Weights of monkeys will be acting downwards therefore net Downwards force is balanced by tension

T= $\left ( 20+26+25\right )32.2+84-135=2235.2 lb-ft/s^2$

5 0

3 years ago

Suppose the entire population of the world gathers in ONE spot and everyone jumps at the sound of a prearranged signal. While ev

puteri [66]

Answer:

(b) Yes, the earth gains momentum but the change in momentum of the earth is much lesser compared to that of everyone in the air. The resistance to motion (inertia of the earth), which is a function of its mass is so great that the earth's acceleration is small in the given time frame.

Explanation:

From Newton's second law which can be stated mathematically as

F = m(v-u)/t = ma.

By Newton's law of gravitation, there is a force between the earth and everyone in the air. This force is responsible for the change in momentum of everyone in the air and this force gives them an acceleration equal to g = 9.80m/s². By Newton's law of gravitation and Newton's third law of motion, this force is also equal to the force exerted by everyone on the earth.

For this to be true,

F = M (everyone) ×a (everyone) = M(earth) × a (earth).

And

a (earth) = {M (everyone) ×a (everyone) }/M (earth)

Then

a (earth) must be lesser than a (everyone) since M(earth) >> M(everyone).

a = change in momentum/ time

Therefore the earth will have a much lesser change in momentum which is the reason we won't notice the earth's movement.

Thank you for reading.

6 0

3 years ago

Write fulk form of FPS?​

Write fulk form of FPS?