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Mamont248 [21]
2 years ago
11

What is the concentration of acetic acid if three 65.0 mL samples of actic acid were neutralized with 16.8 mL, 18.2 mL, and 17.3

5 mL of 0.5.00 M KOH. (Hint: KOH and acetic acid react in a 1 to 1 mole ratio)​
Chemistry
1 answer:
nydimaria [60]2 years ago
8 0

M₁V₁=M₂V₂

65 x M₁ = 16.8 x 0.5

M₁ = 0.129

65 x M₁ = 18.2 x 0.5

M₁ = 0.14

65 x M₁ = 17.35 x 0.5

M₁ = 0.133

Average = 0.129 + 0.14 + 0.133 = 0.134 M

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1. In this case, according to the reaction, we can infer that 799 kJ of energy are evolved (given off, released) it means that the enthalpy of reaction is negative as the reactants have more energy than the products; which means this is an exothermic reaction.

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