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Mamont248 [21]
2 years ago
11

What is the concentration of acetic acid if three 65.0 mL samples of actic acid were neutralized with 16.8 mL, 18.2 mL, and 17.3

5 mL of 0.5.00 M KOH. (Hint: KOH and acetic acid react in a 1 to 1 mole ratio)​
Chemistry
1 answer:
nydimaria [60]2 years ago
8 0

M₁V₁=M₂V₂

65 x M₁ = 16.8 x 0.5

M₁ = 0.129

65 x M₁ = 18.2 x 0.5

M₁ = 0.14

65 x M₁ = 17.35 x 0.5

M₁ = 0.133

Average = 0.129 + 0.14 + 0.133 = 0.134 M

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The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.

Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.

Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.

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