Answer:
0.075 M
Explanation:
5Fe²⁺(aq) + MnO₄⁻(aq) + 8H⁺(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(ℓ)
Using the moles of Fe²⁺ that reacted, we can <em>calculate the reacting moles of MnO₄⁻</em>:
0.0450 mol Fe⁺² * = 0.0090 mol MnO₄⁻
Now we divide the moles of MnO₄⁻ by the volume in order to <u>calculate the molarity of the solution</u>, keeping in mind that 120.0 mL = 0.120 L.
0.0090 mol MnO₄⁻ / 0.120 L = 0.075 M