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2 years ago

8

Split the timing circuit below into 3 blocks by drawing 2 vertical lines across it, label each of the blocks stating whether it

is the input, output or process
also I need this for tmrw (14 june) soooo

1 answer:

garik1379 [7]2 years ago

3 0

Answer:

i can Help you but iam using my phone so typing is really hectic. reach me via app on +254743503332

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In a steam power plant, 1 MW is added in the boiler, 0.58 MW is taken out in the condenser and the pump work is 0.02 MW.

Free_Kalibri [48]

Answer:

a) $\eta = 42\,\%$ , b) $COP_{R} = 29$

Explanation:

a) The thermal efficiency is:

$\eta = \frac{\dot Q_{in} - \dot Q_{out}}{\dot Q_{in}}\times 100\,\%$

$\eta = \frac{1\,MW-0.58\,MW}{1\,MW} \,\times 100\,\%$

$\eta = 42\,\%$

b) The coefficient of performance is:

$COP_{R} = \frac{\dot Q_{L}}{\dot W}$

$COP_{R} = \frac{0.58\,MW}{0.02\,MW}$

$COP_{R} = 29$

3 0

3 years ago

An air mass usually forms in an area of____.

hoa [83]

I think it’s b hopefully it is

3 0

3 years ago

Read 2 more answers

Diodes can be used to protect electronic components from certain flowing in another Direction describe another application outsi

Anvisha [2.4K]

Answer:

Plumbing using a one-way check valve to stop water flowing back on a pump when the pump shuts off.

Explanation:

Diodes are like check valves, keeping current from flowing both ways. Used to create d.c. out of a.c by rectification. Also to block flow if d.c. power like a battery is hooked up in reverse polarity.

4 0

3 years ago

Coastal regions are often affected by nearby ocean currents. The map shows how different ocean currents affect the United States

Effectus [21]

Effect of Ocean currents on the Coastal regions are described below.

Explanation:

1.Ocean currents effects the temperature of the region they travel through. Warm currents increase the temperature of the coasts along which they move. Sea breezes that blow over warm currents get warmed in turn and absorb moisture. Then they carry the warmth and moisture to neighboring coastal areas.

2.When land borders the ocean, the currents of the ocean warm or cool it, depending on the nature of the particular current that flows by that land. In cases where a warm current flows along a particular coast, that coastal area will generally be warmer than it would otherwise be if it were landlocked.

3.They produce high and low tides along coastal regions.They move vertically pushing warm water and nutrients to the surface along coastal regions.

4.The circumpolar current merges the waters of the Atlantic, Indian, and Pacific Oceans and carries up to 150 times the volume of water flowing in all of the world's rivers.

5 0

4 years ago

Air enters a 200 mm diameter adiabatic nozzle at 195 deg C, 500 kPa and 100 m/s. It exits at 85 kPa. If the exit diameter is 158

ahrayia [7]

Answer:

$v_2 = 160.23 m/s$

$T_2 = 475.797 k$

Explanation:

given data:

Diameter = $d_1 = 200mm$

$t_1 =195 degree$

$p_1 =500 kPa$

$v_1 = 100m/s$

$p_2 = 85kPa$

$d_2 = 158mm$

from continuity equation

$A_1v_1 = A_2v_2$

$v_2 = \frac{\frac{\pi}{4}d_1^2 v_1^2}{\frac{\pi}{4}d_2^2}$

$v_2 = \frac{d_2v_1}{d_2^2}$

$v_2 = [\frac{d_1}{d_2}]^2 v_1$

$= [\frac{0.200}{0.158}]^2 \times 100$

$v_2 = 160.23 m/s$

by energy flow equation

$h_1 + \frac{v_1^2}{2} +gz_1 +q =h_2 + \frac{v_2^2}{2} +gz_2 +w$

$z_1 =z_2$ and q =0, w =0 for nozzle

therefore we have

$h_1 -h_2 =\frac{v_1^2}{2} -\frac{v_2^2}{2}$

$dh = \frac{1}{2} (v_1^2 -v_2^2)$

but we know dh = Cp dt

hence our equation become

$Cp(T_2 -T_1) = \frac{1}{2} (v_1^2 -v_2^2)$

$Cp (T_2 -T_1) = 7836.94$

$(T_2 -T_1) = \frac{7836.94}{1.005*10^3}$

$(T_2 -T_1) = 7.797$

$T_2 = 7.797 +468 = 475.797 k$

8 0

3 years ago