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SVEN [57.7K]
3 years ago
15

Sketch the velocity profile for laminar and turbulent flow.

Engineering
1 answer:
Margarita [4]3 years ago
4 0

Answer:

The laminar flow is generally given in high viscosity fluids such as honey or oil, it has the characteristic of flowing in an orderly manner, the walls of the tube have a zero speed while in the center it has a maximum speed.

turbulent flow is characterized by fluid velocity vectors presenting themselves in a disorderly manner and in all directions.

I attached the drawings for the velocity profile in laminar and turbulent flow.

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To reduce the drag coefficient and thus improve the fuel efficiency of cars,the design of side rearview mirrors has changed dram
marissa [1.9K]

Answer:

Amount of fuel used per year is supposed to be 34150 KJ/kg

4 0
3 years ago
In order to break even, your minimum selling price must be __________ your variable costs.
Gelneren [198K]
Your minimum selling price must be HIGHER THAN your variable costs
7 0
3 years ago
A steel bar 100 mm long and having a square cross section 20 mm x 20 mm is pulled in
Ierofanga [76]

Answer:

222.5 Gpa

Explanation:

From definition of engineering stress, \sigma=\frac {F}{A}

where F is applied force and A is original area

Also, engineering strain, \epsilon=\frac {\triangle l}{l} where l is original area and \triangle l is elongation

We also know that Hooke's law states that E=\frac {\sigma}{\epsilon}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}

Since A=20 mm* 20 mm= 0.02 m*0.02 m

F= 89000 N

l= 100 mm= 0.1 m

\triangle l= 0.1 mm= 0.1\times 10^{-3} m

By substitution we obtain

E=\frac {89000\times 0.1}{0.02^{2}\times 0.1\times 10^{-3}}=2.225\times 10^{11}= 225.5 Gpa

5 0
3 years ago
Find the mass if the force is 18 N and the acceleration is 2 m/s2
Nana76 [90]

Explanation:

f = ma

m = f/a

= 18N / 2m/s2

= 9kg

5 0
3 years ago
Read 2 more answers
With 64 KB of memory and 8 bits in each memory location, how wide should the address bus be to access all 64 KB of memory? (k =
marishachu [46]

Answer:

16-bit wide

Explanation:

In order to find the width of the address bus, we need first to know how many memory cells it is needed to address.

If the size memory is 64 KB, this means that the memory size, in bytes, is equal to the following quantity:

64 KB = 2⁶ * 2¹⁰ bytes = 2¹⁶ bytes.

In order to address this quantity of cell positions, the address bus must be able to address 2¹⁶ bytes, so it must have 16-bit wide.

3 0
3 years ago
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