Answer:
(a)Volume in liters=5.3 liters.
(b)Volume in liters/minute=31.8 liters/minute.
Explanation:
Given:
Diameter of cylinder ,D=150 mm
Stroke,L=300 mm
Time ,t=10 sec
we know that swept volume of cylinder
![V_{s}=\dfrac{\pi }{4}\times D^2\times L](https://tex.z-dn.net/?f=V_%7Bs%7D%3D%5Cdfrac%7B%5Cpi%20%7D%7B4%7D%5Ctimes%20D%5E2%5Ctimes%20L)
So
![V_{s}=0.0053 m^3](https://tex.z-dn.net/?f=V_%7Bs%7D%3D0.0053%20m%5E3)
(a) Volume in liters =5.3 liters ( 1
=1000 liters)
(b) When we divide swept volume by time(in minute) we will get liters/minute.
We know that 1 minute=60 sec
⇒10 sec=
minute
So volume displace in liters/minute=31.8 liters/minute.
Answer:
7.05 Hz
Explanation:
The natural frequency of a mass-spring system is:
![f = \frac{1}{2 \pi}\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%20%5Cpi%7D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D)
To determine the constant k of the spring we use Hooke's law:
Δl = F / k
k = F / Δl
In the first case the force was the weight of the 20 kg mass and the Δl was 20 mm.
F = m * a
F = 2 * 9.81 = 19.6 N
Then:
k = 19.6 / 0.02 = 980 N/m
Therefore:![f = \frac{1}{2 \pi}\sqrt{\frac{980}{0.5}} = 7.05 Hz](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%20%5Cpi%7D%5Csqrt%7B%5Cfrac%7B980%7D%7B0.5%7D%7D%20%3D%207.05%20Hz)
No hablo espanol perdon amigo
Answer:
The solution code is written in Java.
- double [] alpha = new double[50];
-
- for(int i =0; i < 25; i++){
- alpha[i] = i * i;
- }
-
- for(int j = 25; j < 50; j++){
- alpha[j] = j * 3;
- }
Explanation:
Firstly, the syntax to declare an array variable <em>alpha</em> of type double and initialize it with 50 components is presented in Line 1.
Next, use a for-loop to traverse through the first 25 components (Line 3). Use * operator to multiply index variable by itself (to square it) and assign it to the current component of the<em> alpha</em> array (Line 4).
Create another for-loop to traverse through the last 25 components (Line 7). This time, multiply the index variable with 3 and assign it to the current component of the <em>alpha</em> array (Line 8).