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MaRussiya [10]
3 years ago
11

If someone were monitoring your vital signs (like your heart rate, oxygen content in your blood, blood pressure, etc.) every hou

r in a hospital, you would
likely want them to be both accurate and precise in their measurements. Make an argument for why what you think is more important, accuracy or
precision?
Physics
1 answer:
Lilit [14]3 years ago
7 0

Answer:

Accuracy

Explanation:

I think accuracy is more important. When it comes to vital organs in the body, the exactness of getting the measurement is paramount. Accuracy deals with getting very close, almost exact you may say, to a known standard. Precision on the other hand, deals with how easy a measurement can be retaken, reproduced or remade, irrespective of how far or close they are from the accepted norm.

From this, we can agree that precision neglects the most important factor, closeness or say, exactness. Precision isn't bothered by it. And while that can be excused in a few instances, it certainly can not be permitted when it comes to life, or organs of the body

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Briefly explain the difference between being self-centered and
tensa zangetsu [6.8K]

Answer:

Explanation:

Self centered means you think about yourself and can sometimes mean that you're arrogant. Self aware means you are aware of certain things you do. Self centered has a negative connotation while self aware has a positive one.

6 0
4 years ago
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It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in
Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

We can derive the formula v^2=v_0^2+2ad from them.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Where in the first step of the last row we just multiplied everything by 2a. Since x-x_0 is the displacement d, we have proved that v^2=v_0^2+2ad

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration 4000 m/s^2:

v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s

7 0
3 years ago
The first model of the atom was developed through scientific experimentation and data analysis with water vapor and gases. obser
stellarik [79]

Answer:

The answer is C. thinking about the smallest particles of matter without experimenting.

6 0
3 years ago
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Why does it take the water in a swimming pool some time to heat up during a hot day?
BartSMP [9]
Because the top layer of a pool will be warmer than the bottom layer, that why filtration is important to cycle the water evenly.
5 0
4 years ago
WILL MARK AS BRAINLIEST!!!!!!
yaroslaw [1]

M1V1 + M2V2 = M1V1' + M2V2'

where:

M1 is the mass of the large marble = 0.05 kg

V1 is the initial velocity of the large marble = 0.6 m/sec

M2 is the mass of the small marble = 0.03 kg

V2 is the initial velocity of the small marble = 0 m/sec (marble is at rest)

V1' is the final velocity of the large marble = -0.2 m/sec

V2' is the final velocity of the small marble that we want to calculate

Substitute with the givens in the above equation to get V2' as follows:

M1V1 + M2V2 = M1V1' + M2V2'

(0.05)(0.6) + (0.03)(0) = (0.05)(-0.2) + 0.03V2'

0.03 = -0.01 + 0.03V2'

0.03V2' = 0.03+0.01 = 0.04

V2' = 0.04/0.03

V2' = 1.334 m/sec

4 0
3 years ago
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