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VLD [36.1K]
2 years ago
13

How many grams of oxygen gas (02) are needed to completely react with 9.30 moles

Chemistry
1 answer:
Luba_88 [7]2 years ago
6 0

Answer:

223 g O₂

Explanation:

To find the mass of oxygen gas needed, you need to (1) convert moles Al to moles O₂ (via the mole-to-mole ratio from reaction coefficients) and then (2) convert moles O₂ to grams O₂ (via the molar mass). When writing your ratios/conversions, the desired unit should be in the numerator in order to allow for the cancellation of the previous unit. The final answer should have 3 sig figs because the given value (9.30 moles) has 3 sig figs.

4 Al + 3 O₂ ----> 2 Al₂O₃
^         ^

Molar Mass (O₂): 32.0 g/mol

9.3 moles Al          3 moles O₂              32.0 g
-------------------  x  ---------------------  x  --------------------  =  223 g O₂
                              4 moles Al               1 mole

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Willam adds two values following the rules for using significant figures in computations
Aleksandr [31]
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5 0
3 years ago
If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
Lynna [10]

Answer:

32 mols of water

Explanation:

2H2 + O2 ==> 2H2O

What your givens are telling you and what the equation is saying is that

for every mol of O2, you get 2 mols of H2O

So you could do it with the proportion about.

1/16 = 2/x                 Cross multiply

x = 16 * 2

x = 32

3 0
3 years ago
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What is the molar mass of Cr3(AsO4)2?<br> g/mol
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7 0
3 years ago
How many moles of the product fecl3 do you make, when 8moles of fe react with excess cl2
tatuchka [14]

To figure out questions related to reacting moles/masses, the first step is always to write a complete balanced equation.

2Fe (s) + 3Cl2 (g) → 2FeCl3 (s)

Since Cl2 is the excess reactant, and Fe is the limiting reactant, we can simply find the number of moles of the product by comparing the mole ratio of the limiting reactant to the mole ratio of the product from the equation.

From the equation, mole ratio of Fe:FeCl3 = 2:2 = 1:1, the number of moles of product is exactly the same as the number of moles of the limiting reactant, which makes it 8 moles.

Note that if the mole ratio is not 1:1, you have to do some calculations to make sure the no. of moles is balanced at the end. Which means, if the mole ratio happened to be 1:2, the no. of moles of the product would be 8x2=16 instead.

So, your answer is 8 moles.

7 0
3 years ago
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When the pressure that a gas exerts
Ronch [10]

Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

5 0
3 years ago
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