Answer:
See below
Explanation:
<u>Specific Heat of water</u> = 4.186 J/(g-C)
J/(g-C) multiplied by g and C results in J
4.186 * 540 * (95-32) = <u>142 407 .72 J</u>
Mass of water : 0.45 g
<h3>Further explanation</h3>
Given
1.5 g ethanoic acid
Required
Mass of water
Solution
Reaction
<em>CH₃COOH + NaOH ⇒H₂O + CH₃COONa</em>
mol CH₃COOH(MW=60 g/mol) :
= mass : MW
= 1.5 : 60
= 0.025
mol H₂O from the equation :
= 0.025(mol ratio CH₃COOH : H₂O= 1 : 1)
Mass of water :
= mol x MW water
= 0.025 x 18 g/mol
= 0.45 g
Answer : The true statements are:
(a) Emulsions are a type of colloid
(b) The particles of a colloid are larger than the particles of a solution
(d) Many colloids scatter light (tyndal effect)
Explanation :
Colloid : It is defined as the solution in which the one substance is insoluble in another solution that means the insoluble substance rotating in the solution.
The particles of a colloid are larger than the particles of a solution.
Colloid do not separate on standing.
Cannot be separated by filtration.
Scatter light (Tyndall effect).
For example :
Milk is considered as a colloid because various substances (fats, proteins etc..) are present in milk which are suspended in a solution.
Suspension : It is a heterogeneous mixture in which some of the particles are settle down in the mixture on standing or over time.
The particles in a suspension are far larger than those of a solution.
Emulsion : It is a mixture of two or more liquids that are normally immiscible.
Emulsions are a type of colloid.
Answer:
= 200 mL
Explanation:
Using the dilution formula;
M1V1 = M2V2 ;
Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.
M1 = 2.0 M
V1 = 50 mL
M2 = 0.50 M
V2 = ?
V2 = M1V1/M2
= ( 2.0 × 50 )/ 0.5
= 200 mL
Therefore, the volume after dilution will be, 200 mL
