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8090 [49]
3 years ago
12

Electromagnetic waves will travel the SAME SPEED (speed of light) WITHIN a medium as it does WITHOUT a medium. Question options:

True False
Chemistry
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

True

Explanation:

The speed that electromagnetic waves will travel within any medium is the same as those without a medium. The speed of electromagnetic wave is a constant and does not depend on the material of the medium.

  • Electromagnetic waves are waves that do not require a material medium for their propagation.
  • They are able to pass through vacuums and mediums with particles at constant speed.
  • It is mechanical waves whose speed is medium dependent.
  • Mechanical waves have varying speed based on the mediums they move through.
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➡ ANSWER

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A blank is a condition that strays from normal homeostasis.
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3 years ago
A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

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Molecule A is: A. Isocitrate B. Pyruvate C. Alpha-ketoglutarate D. Oxaloacete E. None of the above
hodyreva [135]

Answer:... I'm sorry.. I think you're missing something

Explanation:

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