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2 years ago

Explain the uses of Electrophorus

Physics

1 answer:

Maslowich2 years ago

8 0

Answer:

Explanation:

Comment

Interesting creature.

These creatures are the only survivors from an era long past, where nothing else has survived. They are eels capable of discharging a large electrical current. A pack of them (they can hunt in groups) can kill just about anything.

Tribes use and tame them to guard the tribe's tame Electrophorus. They are bread and maintained in schools. While the charge is huge, once discharged, these creatures take a very long time to recharge, so they are not entirely invincible.

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1 point<br> How much force is needed to accelerate an 84-kg boulder at a rate of 6.4<br> m/s/s? *

Katen [24]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 84 × 6.4

We have the final answer as

Hope this helps you

5 0

2 years ago

14) A race car accelerates from rest to a velocity of 41 m/s in 480 m. What is the acceleration of the race car?

natka813 [3]

Answer:

Explanation:

V₀ = 0 m/s

V = 41 m/s

S = 480 m

___________

a - ?

Distance traveled:

S = (V² - V₀²) / (2*a)

Acceleration :

a = (V² - V₀²) / (2*S)

a = (41² - 0²) / (2*480) = 1.75 m/s²

8 0

1 year ago

Suppose you have a dipole that's free to move in any way (including rotate - imagine it floating in space). And there's an objec

Setler [38]

Complete Question

The complete question shown on the first uploaded image

Answer:

The force on Q due to dipole is Attractive

The charge Q exerts attractive force on the dipole

Yes from the above parts, force depends on the sign of charge

$F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]$

The magnitude o force decrease by a factor of 8.0 times

Explanation:

The explanation is shown on the second uploaded image

5 0

3 years ago

At a baseball game, the batter hit a fly ball at time t = 0 s. The outfielder caught the ball at t = 5.8 s. When was the ball at

Agata [3.3K]

We have the following equation for height:
h (t) = (1/2) * (a) * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height.
The value of the acceleration is:
a = -g = -9.8 m / s ^ 2
For t = 0 we have:
h (0) = (1/2) * (a) * 0 ^ 2 + vo * 0 + h0
h (0) = h0
h0 = 0 (reference system equal to zero when the ball is hit).
For t = 5.8 we have:
h (5.8) = (1/2) * (- 9.8) * (5.8) ^ 2 + vo * (5.8) + 0
(1/2) * (- 9.8) * (5.8) ^ 2 + vo * (5.8) + 0 = 0
vo = (1/2) * (9.8) * (5.8)
vo = 28.42
Substituting values we have:
h (t) = (1/2) * (a) * t ^ 2 + vo * t + h0
h (t) = (1/2) * (- 9.8) * t ^ 2 + 28.42 * t + 0
Rewriting:
h (t) = -4.9 * t ^ 2 + 28.42 * t
The maximum height occurs when:
h '(t) = -9.8 * t + 28.42
-9.8 * t + 28.42 = 0
t = 28.42 / 9.8
t = 2.9 seconds.
Answer:
The ball was at maximum elevation when:
t = 2.9 seconds.

8 0

3 years ago

Read 2 more answers

If all of the forces acting on an object are balanced, then:

kondaur [170]

A. the direction the object is moving in will not change.

B. the acceleration of the object will be 0 m/s2

Explanation:

We can answer this problem by using Newton's second law of motion:

$\sum F = ma$

where

$\sum F$ is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, all the forces acting on the object are balanced, therefore the net force is zero:

$\sum F=0$

which means that also the acceleration is zero:

$a=0$

Acceleration is equal to the rate of change of velocity: therefore, zero acceleration means that the velocity of the object does not change. We can now analyze the given statements:

A. the direction the object is moving in will not change. --> TRUE, because the velocity is not changing.

B. the acceleration of the object will be 0 m/s2 --> TRUE, as we stated above

c. the object will not be in motion. --> FALSE: we just know that its velocity is constant, but it can be different from zero

D. the velocity of the object will be 0 m/s. --> FALSE, for the same reason stated in C

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

3 0

3 years ago

Explain the uses of Electrophorus ​

Explain the uses of Electrophorus