Question

1. A stationary 50 tonne submarine fires a missile of mass 40kg at

Answer 1

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne=$50\times 1000=50000kg$

Mass of the missile m=40  kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

$V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s$