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GREYUIT [131]
3 years ago
13

The plunger of a syringe is pulled up halfway, as shown in the picture. With the plunger in this position, how does the volume o

f the gas and the pressure inside the syringe differ from when there was no gas in the syringe?
top~ANSWER:increases
bottom~ANSWER:decreases
Physics
2 answers:
noname [10]3 years ago
5 0

Explanation. A gas will expand to fill its container. Pulling the plunger of the syringe creates a low pressure inside the syringe (a vacuum)

ICE Princess25 [194]3 years ago
3 0

Answer:

The volume of gas inside the syringe increases and the pressure decreases.

Explanation:

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A 4.44 l container holds 15.4 g of oxygen at 22.55°c. what is the pressure?
padilas [110]
We will use the ideal gas equation:
PV = nRT, where n is moles and equal to mass / Mr
P = mRT/MrV
P = 15.4 x 8.314 x (22.55 + 273) / 32 x 4.44
P = 266.3 kPa
5 0
3 years ago
Calculate the potential difference across a 25-Ohm. resistor if a 0.3-A current is flowing through it.
nikdorinn [45]

Answer:7.5V

Explanation:

Ohm's law, V=IR

so, V=0.3×25

V=7.5V

4 0
3 years ago
Read 2 more answers
What is the direction of the force on a positive charge when passing through a magnetic field as indicated in this diagram? Expl
maria [59]

Answer:

The direction of the magnetic force on a moving charge is perpendicular to the plane formed by v and B and follows right hand rule–1 (RHR-1)

Explanation:

hope this helps

3 0
3 years ago
The velocity of a car changes from 15 m/s south to 5 m/s south in 2 seconds what is the acceleration of the car
Leviafan [203]

Acceleration = Change in velocity / time taken

                     = (5 - 15) / 2

                     = -5 ms^-2

4 0
3 years ago
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Chromatic aberration comes from the fact that different wavelengths of light travel at different speeds through the material of
gtnhenbr [62]

Answer:

 y_red / y_blue = 1.11

Explanation:

Let's use the constructor equation to find the image for each wavelength

         1 /f = 1 /o + 1 /i

Where f is the focal length, or the distance to the object and i the distance to the image

Red light

           1 / i = 1 / f - 1 / o

           1 / i_red = 1 / f_red - 1 / o

           1 / i_red = 1 / 19.57 - 1/30

           1 / i_red = 1,776 10-2

           i_red = 56.29 cm

Blue light

            1 / i_blue = 1 / f_blue - 1 / o

            1 / i_blue = 1 / 18.87 - 1/30

            1 / i_blue = 1,966 10-2

            i_blue = 50.863 cm

Now let's use the magnification ratio

             m = y ’/ h = - i / o

             y ’= - h i / o

Red Light

            y_red ’= - 5 56.29 / 30

            y_red ’= - 9.3816 cm

Light blue

            y_blue ’= 5 50,863 / 30

            y_blue ’= - 8.47716 cm

The ratio of the height of the two images is

            y_red ’/ y_blue’ = 9.3816 / 8.47716

            y_red / y_blue = 1,107

            y_red / y_blue = 1.11

5 0
3 years ago
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