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san4es73 [151]
4 years ago
13

Which of these processes are chemical reactions

Physics
1 answer:
White raven [17]4 years ago
5 0

Explanation:

  • In chemical reactions, chemical changes occur.
  • Atoms are simply rearranged and new bonds are formed.
  • Chemical reactions are driven by a need for atoms to attain stability in their structure.
  • In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
  • Most these reactions are not easily reversible.
  • They are usually accompanied by the release of energy.

Learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

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Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.4×109 electrons from one disk to the
allsm [11]

Answer:

r = 6.5*10^-3 m

Explanation:

I'm assuming you meant to ask the diameters of the disk, if so, here's it

Given

Quantity of charge on electron, Q = 1.4*10^9

Electric field strength, e = 1.9*10^5

q = Q * 1.6*10^-19

q = 2.24*10^-10

E = q/ε(0)A, making A the subject of formula, we have

A = q / [E * ε(0)], where

ε(0) = 8.85*10^-12

A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)

A = 2.24*10^-10 / 1.6815*10^-6

A = 1.33*10^-4 m²

Remember A = πr²

1.33*10^-4 = 3.142 * r²

r² = 1.33*10^-4 / 3.142

r² = 4.23*10^-5

r = 6.5*10^-3 m

3 0
3 years ago
What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se
UNO [17]
The weight (W) of an object is the product of its mass (m) and the acceleration (a). That is,
                                    W = m x a
Substituting the known values give,
                                W = (60 kg) x (3.75 m/s²) = 225 N
Thus, the object's weight is 225 N. The answer is letter D.
0 0
4 years ago
Read 2 more answers
The gravitational force of attraction between two masses is F
Rzqust [24]

Hi there!

We can use the equation for gravitational force:
F_g = \frac{Gm_1m_2}{r^2}

Fg = force due to gravity (N)

m1, m2 = masses of objects (kg)

r = distance between the center of mass of the objects (m)

G = gravitational constant

1.

Using the equation:
F'_g = \frac{G(3m_1)(3m_2)}{r^2} = 9F_g

The force would be <u>9 times larger. </u>

2. (Repeat?)

3.

The square of distance is inversely related, so:
F'g= \frac{Gm_1m_2}{(\frac{2}{3}r)^2} = \frac{Gm_1m_2}{\frac{4}{9}r^2} = \frac{9}{4}F_g

The force is <u>9/4ths times larger.</u>

4.

Combining:
F'_g = \frac{G(2m_1)(2m_2)}{(3r)^2} = \frac{4Gm_1m_2}{9r^2} = \frac{4}{9}F_g

The force is <u>9/4ths times larger.</u>

<u></u>

5.

F'g = \frac{G(2m_1)m_2}{(4r)^2} = \frac{2Gm_1m_2}{16r^2} = \frac{1}{8}F_g

The force is <u>1/8th the original.</u>

6.

Equation for gravitational field:
g = \frac{Gm_e}{r_e^2}

g = acceleration due to gravity (m/s²)

G = gravitational constant

me = mass of earth (kg)
re = radius of earth (m)

With the following transformations:
g' = \frac{G(2m_e)}{(\frac{1}{3}r)^2} = \frac{2Gm_e}{\frac{1}{9}r^2} = 18g

The acceleration due to gravity is <u>18 times as large.</u>

5 0
2 years ago
A golfer hits a golf ball with a club head velocity of 94 mph. Mass of golf club head (m): 190 g Mass of golf ball (ms): 46 g Co
MAXImum [283]

Answer:

Velocity of golf ball≅ 12.87mph    

Explanation:

Using the theory of conservative momentum to both the club head and the golf ball  we have;

Qi1 + Qi2= Qf1 + Qf2

Qi1: initial momentum for the club head

Qf1: final momentum for the club head

Qi2: initial momentum for the golf ball

Qf2: final momentum for the golf ball

momentum (Q) = Mass x velocity

which means the sum of the momentums of both club head and golf ball has to be the same before and after they have collided.

using the Coeficient of restitution e= 0.83 allows us to know what kind of collision we are dealing with, which is a partially elastic collision since

0> e=0.83 >1.

Qi1= 190 x 94= 17,860 mph.g

Qf1= 190 x Vf1

Qi2= 46 x 0= 0 mph.g

Qf2= 46x Vf2

Using the value of e to determine Vf2 as the final velocity of the golf ball:

e= \frac{Vf2- Vf1}{Vi1 - Vi2}

0.83= \frac{Vf2 - Vf1}{94 - 0}

Vf1= (0.83 x 94)+ Vf2

Vf1= 78.02 + Vf2

Qi1 + Qi2= Qf1 + Qf2

17,860 + 0 = 190xVf1 + 46xVf2    

17,860= 190x (78.02+Vf2) + 46xVf2

17,860= 14,823+ 190xVf2+46xVf2

Vf2≅ 12.87mph                

7 0
3 years ago
Which characteristic of the sun is MOST responsible for keeping the planets in orbit?
Ket [755]
A) Its mass  

I think this is the answer because if another planet had a bigger mass the other planets and the sun itself would orbit it. I am not sure though this is my best guess.
7 0
4 years ago
Read 2 more answers
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