The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.
Answer:
tortoise distance w.r.t sloth is 28.08 m further
Explanation:
given data
average speed v1 = 0.037 m/s
walking speed v2 = 0.076 m/s
time t = 12 min = 720 seconds
to find out
how much tortoise have gone wrt sloth
solution
we find here first tortoise walk that is
distance d1 = v2 × t
distance d1 = 0.076 × 720
distance d1 = 54.72 m
and sloth walk distance
distance d2 = v1 × t
distance d2 = 0.037 × 720
distance d2 = 26.64 m
and so
tortoise distance w.r.t sloth = d1 - d2
tortoise distance w.r.t sloth = 54.72 - 26.64 = 28.08
tortoise distance w.r.t sloth is 28.08 m further
Antelope: uniform motion => V = d/t => d = Vt = 7m/s * t
Lion: uniformly accelerated motion, with initial velocity = 0 => d = [1/2]a*t^2 = [1/2]*[5m/s^2]*t^2
7*t = 2.5*t^2=> 2.5t^2 - 7t =0 => t(2.5t - 7) = 0
2.5t - 7 = 0 => t = 7/2.5 = 2.8 m/s^2
Answer:
53.125m
Explanation:
The displacement of the car, denoted by S, can be calculated using the formula:
S = ut + 1/2at²
Where;
u = initial velocity/speed (m/s)
t = time (s)
a = acceleration (m/s²)
According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?
S = ut + 1/2at²
S = (10 × 5) + 1/2 (0.25 × 5²)
S = 50 + 1/2 (0.25 × 25)
S = 50 + 1/2(6.25)
S = 50 + 3.125
S = 53.125m
