What is the molecular polarity of the following lewis structure

A sample of carbon dioxide has a pressure of 1.2 atm, a volume of

GalinKa [24]

The answer for the following question is mentioned below.

Therefore no of moles present in the gas are 1.12 moles

Explanation:

Given:

Pressure of gas (P) = 1.2 atm

Volume of a gas (V) = 50.0 liters

Temperature (T) =650 K

To calculate:

no of moles present in the gas (n)

We know;

According to the ideal gas equation;

We know;

P × V = n × R × T

where,

P represents pressure of the gas

V represents volume of the gas

n represents no of the moles of a gas

R represents the universal gas constant

where the value of R is 0.0821 L atm mole^{-1} K^-1

T represents the temperature of the gas

As we have to calculate the no of moles of the gas;

n = $\frac{P*V}{R*T}$

n = \frac{1.2*50.0}{0.0821*650}

n = \frac{60}{53.365}

n = 1.12 moles

Therefore no of moles present in the gas are 1.12 moles

3 0

3 years ago

Granite was formed slowly as magma cooled. What is the result of the slow cooling?

Aleksandr-060686 [28]

Igneous rocks from cooling magma. Granite is an igneous rock formed from magmathat cooled slowly underground. As the magma slowly cools, large mineral crystals form.

4 0

2 years ago

Read 2 more answers

The standard emf for the cell using the overall cell reaction below is +2.20 V:

ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: $2Al-6e^{-}\rightarrow 2Al^{3+}$

Reduction: $3I_{2}+6e^{-}\rightarrow 6I^{-}$

---------------------------------------------------------------------------------

Overall: $2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}$

Nernst equation for this cell reaction at $25^{0}\textrm{C}$ -

$E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}$

where n is number of electrons exchanged during cell reaction, $E_{cell}^{0}$ is standard cell emf , $E_{cell}$ is cell emf , $[Al^{3+}]$ is concentration of $Al^{3+}$ and $[Cl^{-}]$ is concentration of $Cl^{-}$

Plug in all the given values in the above equation -

$E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V$

So, $E_{cell}=2.32V$

3 0

2 years ago

The electronegativity of nitrogen (n) is 3.0, while the electronegativity of hydrogen (h) is 2.1. knowing this, consider how the

Goryan [66]

The electronegativity of nitrogen (N) is 3.0, while the electronegativity of hydrogen (H) is 2.1. As it can be seen that nitrogen (N) is more electronegative than that of hydrogen (H),

So electron pairs are attracted towards nitrogen and thus it carries a partial negative charge and hydrogen carries a partial positive charge. The image of electron distribution is attached as follows.

Thus NH₃ is a polar molecule .