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2 years ago

Which diagram shows the resulting wave when they cross at point X?

Physics

1 answer:

zvonat [6]2 years ago

5 0

The resulting wave will have zero amplitude, thus it will form a straight line.

<h3>What is a crest?</h3>

A crest is an upward displacement of a progressive wave.

<h3>What is a trough?</h3>

A trough is a downward displacement of a progressive wave.

<h3>Superimposition of the two waves</h3>

When the two waves meet each other at point X, they will superimpose and cancel out since they have equal amplitude and are in opposite direction.

The resulting wave will have zero amplitude, thus it will form a straight line.

Learn more about crest here: brainly.com/question/1430231

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A cable that weighs 8 lb/ft is used to lift 900 lb of coal up a mine shaft 650 ft deep. Find the work done. Show how to approxim

Harrizon [31]

Answer:

2275000 lb.ft

Explanation:

Let work done on the cable be denoted by: W_ca

Let work done on the coal be denoted by: W_co

Now, dividing the cable into segments, let x represent the length from top of the mine shaft to the segment.

Meanwhile let δx be the length of the segment.

We are told the cable weighs 8 lb/ft. Thus;

Work done on one segment = 8 × δx × x = 8x•δx

Therefore, work done on cable is;

W_ca = ∫8x•δx between the boundaries of 0 and 650

Thus;

W_ca = 4x² between the boundaries of 0 and 650

W_ca = 4(650²) - 4(0²)

W_ca = 1,690,000 lb.ft

Workdone on the 900 lb of coal will be calculated as;

W_co = 900 × 650

W_co = 585000 lb.ft

Thus,

Total work done = W_ca + W_co

Total workdone = 1690000 + 585000

Total workdone = 2275000 lb.ft

6 0

3 years ago

20.0 -kg cannonball is fired from a cannon with muzzle speed of 1000m/s at an angle of 37.0° with the horizontal. A second ball

Dovator [93]

The mechanical energy for the first and the second ball is

$10 ^{7} \: joules.$

Mass of the first ball = 20 kg

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 37°

The maximum height reached by the first ball is,

$= \frac{ u {}^{2} _{1}sin {}^{2} θ}{2g}$

$= \frac{ {1000}^{2} sin {}^{2}37°}{2 \times 9.8}$

$= 18478.69 \: m$

The maximum height of the first cannonball is 17478.69 m.

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 90 °

$= \frac{ u {}^{2} _{2}sin {}^{2} θ}{2g}$

$= \frac{ 1000{}^{2}sin^{2} 90°}{2 \times 9.8}[tex] = 51020.41 \: m$

For the first ball, total mechanical energy= Potential energy at maximum height + kinetic energy at the maximum height

So, the total mechanical energy is,

= mgh \: + \frac{1}{2}mv {}^{2} _{x}[/tex]

$= 20 \times 9.8 \times 18478.64 \times \frac{20}{2} (1000 \: cos37 °)$

$= 10 ^{7} The potential energy at the maximum height, = m _{2}gh$

$= 20 \times 9.8 \times 51020.41$

$= 10 ^{7} \:J$

Therefore, the total mechanical energy for the first and the

$\:second \: cannonball \: is \: 10 ^{7} \:joules.$

To know about energy, refer to the below link:

brainly.com/question/1932868

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5 0

2 years ago

What is the mass of an object that has a weight of 52N? (n=newtons)<br><br>Answer is in kilograms

polet [3.4K]

Hi there!

The answer you are looking for.....

<span>5.3025kg!</span>

Hope this helps you!

Have a great day!

8 0

3 years ago

Acharged particle moving through a magnetic field at right angles to the field with a speed of 36.2 m/s experiences a magnetic f

Arada [10]

Answer:

7212.3 N

Explanation:

F = 7.38 x 10^4 N, v = 36.2 m/s

Let b be the strength of magnetic field and charge on the particle is q.

F = q v B Sin theta

Here theta = 90 degree

7.38 x 10^4 = q x 36.2 x B x Sin 90

q B = 2038.7 .....(1)

Now, theta = 17 degree, v = 12.1 m/s

F = q v B Sin theta

F = 2038.7 x 12.1 x Sin 17 ( q v = 2038.7 from equation (1)

F = 7212.3 N

3 0

3 years ago

A parallel circuit is constructed with three different branches. An ammeter is placed in each of the branches to measure the bra

neonofarm [45]

Answer:

Current in the battery will be 11.7 A

Explanation:

We have given that the there is parallel circuit with three different branches.

Current in each branch is $I_1=2.8A$ , $I_2=4.1A$ , $I_2=4.8A$

We have to find the current I in the battery

It is known that in parallel circuit current is sum of current in each branches

So current in the battery will be equal to

$I=I_1+I_2+I_3$

$I=2.8+4.1+4.8=11.7A$

Therefore current in the battery will be 11.7 A

8 0

3 years ago