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Physics

1 answer:

Dennis_Churaev [7]3 years ago

4 0

Answer:

ummmm none lol

Explanation:

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A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the

otez555 [7]

According to snells law

n1 sin theta1 = n2 sin theta2
n1 = 1.333 (water)
n2 = 2.42 (diamond)
it is given that theta =30 degrees so
by putting the values we have

1.333 sin theta = 2.42 sin 30 

sin theta = (2.42/1.333) *0.5 =65.2 degree
so our conclusion is

the ray's angle of incidence θ1 on the diamond = 65.2 degree.
hope this helps

4 0

4 years ago

PlzHELP

Naddika [18.5K]

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

To calculate displacement, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your displacement is 0. In physics, displacement is represented by Δs.

For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me.

https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php

Hope I helped.

8 0

3 years ago

Two trains A and B of length 400 m each are moving on two parallel tracks with

Vinvika [58]

Answer:

The initial distance between the trains is 1450 m. 

Explanation:

In the question two trains are of equal length 400 m and moves at a uniform speed of 72 km/h. train A is moving ahead of train B. If the train B has to overtake train A it should accelerate.

Train B’s acceleration is $1m/s^2$ and it accelerated for 50 seconds.

 $a=1 m/s^2$ 

t=50 s 

initial speed u=72km/h 

we have to convert this speed into m/s 

 $u=72 \times 5/18=20 m/s$ 

Distance covered in accelerating phase $S=ut+1/2 at^2$ 

 $=20 \times 50+1/2 \times 1 \times 50^2$ 

 $=1000+1250=2250 m$ 

If a train is just behind another, the distance covered by the train located behind during overtaking phase will be equal to the sum of the lengths of the trains.

Here length of train A+length of train $B=400+400=800 m$ 