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1 year ago

11

I need help with my homework please? I will give a lot of points and a brainlist.

1 answer:

Sladkaya [172]1 year ago

4 0

Answer:

1. False

some metals are ferromagnetic

2.True

3. True

4. True

5. False

The strength of electromagnetic can be increased by increasing the number of wire around it

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Where are all stars bornWhat is the brightest star in the night sky? What is its magnitude?

sergij07 [2.7K]

Answer:Stars are born within the clouds of dust and scattered throughout most galaxies.It's the star Sirius in the constellation Canis Major, brightest star in the sky. The bright planet Venus is also up before dawn now. But you'll know Sirius, because Orion's Belt always points to it.With an apparent magnitude of −1.46

Explanation: Brainliest Please!!!!

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2 years ago

What is the minimum force required to increase the energy of a car by 84 J over a distance of 38 m? Assume the force is constant

konstantin123 [22]

Answer:

2.210N

Explanation:

Workdone = Force x distance

Distance = 38m , Workdone = 84J

Hence 84J = Force x 38m

Force = 84J / 38m

Force = 2.210N =2.2N

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2 years ago

Virginia��s blue ridge mountains were pushed up when the north american and african continents collided in a process known as

Amiraneli [1.4K]

It is either c. folding or b. faulting

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2 years ago

Read 2 more answers

An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the

alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

$X=V_{o}*t + \frac{a*t^{2}}{2}$ Replacing the known values:

$1500=6t+0.9*t^{2}$ Solving for t we get 2 possible answers:

t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0

2 years ago

A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu

dalvyx [7]

Answer:

The frictional torque is $\tau = 0.2505 \ N \cdot m$

Explanation:

From the question we are told that

The mass attached to one end the string is $m_1 = 0.341 \ kg$

The mass attached to the other end of the string is $m_2 = 0.625 \ kg$

The radius of the disk is $r = 9.00 \ cm = 0.09 \ m$

At equilibrium the tension on the string due to the first mass is mathematically represented as

$T_1 = m_1 * g$

substituting values

$T_1 = 0.341 * 9.8$

$T_1 = 3.342 \ N$

At equilibrium the tension on the string due to the mass is mathematically represented as

$T_2 = m_2 * g$

$T_2 = 0.625 * 9.8$

$T_2 = 6.125 \ N$

The frictional torque that must be exerted is mathematically represented as

$\tau = (T_2 * r ) - (T_1 * r )$

substituting values

$\tau = ( 6.125 * 0.09 ) - (3.342 * 0.09 )$

$\tau = 0.2505 \ N \cdot m$

5 0

2 years ago