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inysia [295]
2 years ago
9

What is the relative rate of diffusion of hydrogen and nitrogen ​

Chemistry
1 answer:
vredina [299]2 years ago
3 0

Answer:

2.645

Explanation:

Rate of diffusion formula:

Sqrt(mass2/mass1)

>>sqrt(14/2)

(Note:Hydrogen must exist in dwiatomic, [H2])

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Examine the reactants of the incomplete synthesis reaction. 2Mg + O2 → __________.
Vladimir79 [104]
2MgO
This is called redox reaction. Oxygen is the oxidizing agent to receive 2 electrons from Mg.
Mg is the reducing agent to give 2 electrons to O.
Mg becomes Mg2+ and O becomes O2-. These 2 ions form an ionic structure called MgO
4 0
2 years ago
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Predict where on this graph you would find the GREATEST concentration of atomic mass based on what you know regarding the locati
anastassius [24]

Answer:

The Answer is A

Explanation:

i just did this on usa test prep

4 0
3 years ago
How have observations in the sky enabled humans to explore and travel?
andre [41]

Answer:

Observations of the sky allowed explorers to mark the passage of time both in hours and through the months of the year. Early astronomers also realized that the night sky does not look the same from different places on the Earth.

4 0
2 years ago
PLEASE HELL ME!!!!
vazorg [7]

Answer:

<h3>The answer is 0.045 kg/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of cylinder = 14 kg

Volume of a cylinder = πr²h

where

r is the radius

h is the height

radius =  \frac{diameter}{2}  \\

From the question

h = 25 cm

r =  \frac{4}{2}  = 2 \:  \:  \: cm

The volume of the cylinder is

V =  {2}^{2} (25)\pi \\  = 4 \times 25\pi \\  = 100\pi \\  = 314.159265...

We have

volume = 314.159 cm³

The density of the cylinder is

density =  \frac{14}{314.159}  \\  = 0.044563421...

We have the final answer as

<h3>0.045 kg/cm³</h3>

Hope this helps you

7 0
3 years ago
Read 2 more answers
Using the following thermochemical data: 2Y(s) + 6HF(g) → 2YF3(s) + 3H2(g) ΔH° = –1811.0 kJ/mol 2Y(s) + 6HCl(g) → 2YCl3(s) + 3H2
Luba_88 [7]

Answer:

ΔH° =   182.4 kJ/mol

Explanation:

The ΔH wanted is for the reaction :

YF3(s) + 3HCl(g) → YCl3(s) + 3HF(g)

This is a Hess Law problem where e will have to algebraically manipulate the first and second equations , add them together, and arrive at the desired equation above.

Notice if we reverse the first equation and divide it by 2 and add to the the second only divided by two, we will arrive to the desired equation:

2YF3(s) + 3H2(g)  →  2Y(s) + 6HF(g)  ΔH° = 1811.0 kJ/mol (change sign)

dividing by two :

YF3(s) + 3/2H2(g)  →  Y(s) + 3HF(g)     ΔH° =  905.5 kJ/mol  Eq 1

2Y(s) + 6HCl(g) → 2YCl3(s) + 3H2(g) ΔH° = –1446.2 kJ/mol

dividing this one by two,

Y(s) + 3HCl(g) → YCl3(s) + 3/2 H2(g) ΔH° = –1446.2 kJ/mol/2 = - 723.10 kJ/mol Eq 2

Now adding 1 and 2

YF3(s) + 3/2H2(g)  →  Y(s) + 3HF(g)     ΔH° =  905.5 kJ/mol  Eq 1

Y(s) + 3HCl(g) → YCl3(s) + 3/2 H2(g) ΔH° = –1446.2 kJ/mol/2 = - 723.10 kJ/mol Eq 2

________________________________________________________

YF3(s) + 3HCl(g) → YCl3(s) + 3HF(g).   ΔH° =  905.5 + (-723.1) kJ/mol

ΔH° =   182.4 kJ/mol

Notice how the Y(s) and H2 cancel nicely and the coefficients are the right ones.

8 0
3 years ago
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