All categories

3 years ago

The temperature of 200 mL of gas

Chemistry

1 answer:

Elden [556K]3 years ago

6 0

Answer:

691.6 torr

Explanation:

Given data:

Initial temperature = 273 K

Initial pressure = 1 atm

Final temperature = -25 °C (-25 + 273 = 248 k)

Final pressure = ?

Solution:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Now we will put the values in formula.

P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁

P₂ = 1 atm × 248 K / 273 k

P₂ =248 atm. K / 273 K

P₂ = 0.91 atm

In torr:

0.91 × 760 = 691.6 torr

You might be interested in

Iron pyrite, FeS2, is known as Fool's Gold because it is a shiny yellow solid which is similar in appearance to gold. Iron pyrit

kobusy [5.1K]

Answer:

Explanation:

The algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

In order to know the formula of the negative Sulfur ion in pyrite, we must determine its oxidation state.

Let us make the make the oxidation number of sulfur = x

Therefore, FeS₂:

+2 +2x = 0

+2 = -2x

x = -1

The formula of the negative ion is S⁻

4 0

3 years ago

What is it called when a consume wastes and dead organisms??????

8_murik_8 [283]

<span>Decomposers and a few insects.</span>

8 0

3 years ago

Calculate the vapor pressure (in torr) at 298 K in a solution prepared by dissolving 38.5 g of the non-volatile non-electrolye u

Free_Kalibri [48]

Answer: The vapor pressure of methanol solution at 298K is 107.12 torr

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

$\frac{p^o-p_s}{p^o}=i\times x_2$

where,

$\frac{p^o-p_s}{p^o}$ = relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

$x_2$ = mole fraction of solute = $\frac{\text {moles of solute}}{\text {total moles}}$

Given : 38.5 g of urea is present in 142 g of methanol

moles of solute (urea) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{38.5g}{60g/mol}=0.64moles$

moles of solvent (methanol) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{142g}{32g/mol}=4.4moles$

Total moles = moles of solute + moles of solvent = 0.64 + 4.4 = 5.04

$x_2$ = mole fraction of solute = $\frac{0.64}{5.04}=0.127$

$\frac{122.7-p_s}{122.7}=1\times 0.127$

$p_s=107.12torr$

Thus the vapor pressure of methanol solution at 298K is 107.12 torr

3 0

3 years ago

2. What is the mass of one mole of Na?

borishaifa [10]

Sodium, Atomic mass: 22.989769 g
You can see in a periodic table

5 0

3 years ago

A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As

TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

$P.V=n.R.T=\frac{m}{M} .R.T$

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

$m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g$

7 0

3 years ago