Question

The temperature of 200 mL of gas

Answer 1

Answer:

691.6 torr

Explanation:

Given data:

Initial temperature = 273 K

Initial pressure = 1 atm

Final temperature = -25 °C (-25 + 273 = 248 k)

Final pressure = ?

Solution:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure  

T₂ = Final temperature

Now we will put the values in formula.

P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁  

P₂ = 1 atm × 248 K / 273 k

P₂ =248  atm. K / 273 K

P₂ = 0.91 atm  

In torr:

0.91  × 760 = 691.6 torr